Say that line m is described by the function m(x) and line l by l(x). If m is a reflection of l in the x axis, then it follows that m(x) = -l(x). Try drawing a sketch to satisfy yourself of this. At the intersection(s) of l and m, m(x) = l(x). But we have also stated that m(x) = -l(x). This can only be true if the value of both functions (i.e. the y coordinate, s) is zero.
nx - m = p so x = (m+p)/n
m *n (m multiplied by n) would be mn.
1 cm cubed = 1 cm X 1 cm X 1 cm 1 cm = .01 m, so 1 cm cubed = .01 m X .01 m X .01 m Therefore, 1 cm cubed = .000001 m cubed, and 243 cm cubed = 243 X .000001 = .000243 m cubed. In summary, multiply cm cubed by .000001 to get m cubed.
The volume of a cylinder equals the area of the base times the height, which equals pi x radius squared x height. Inserting the numbers, V = pi x (2 m.) squared x 5 m. = pi x 4 m. squared x 5 m. = 20 x pi meters cubed or 20 x pi cubic meters.
032 in Scientific Notation = 0.32 x 102
It is 0.877
Add together the individual numerals (M = 1000, D = 500, C = 100, L = 50, X = 10, V = 5, I = 1) unless a smaller numeral precedes a larger one in which case subtract it from the larger ones. → 1231 = 1000 + 100 + 100 + 10 + 10 + 10 + 1 = MCCXXXI
Suppose m is the required multiplier.Then multiplication by m would increase any x by 11, that is, x * m = x + 11 for all x x * m - x = 11 x*(m - 1) = 11 m - 1 = 11/x m = 1 + 11/x But that means that m is not defined for x = 0 and there is a different m for every non-zero x.
m=8 l=6 y=4 m X m = 8 X 8 = 64 =ly m X l = 8 X 6 = 48 = ym
for any non zero no. x, x^0=1 the proof is as follows, consider the two no.s x^m and x^n,where m and n are two non zero no.s. now let us assume without any oss of generality,that m>n,hence (x^m)/x^n=(x*x*x....m times)/(x*x*x...n times) now on the r.h.s, n no. of x in the denominator will cancel out n no. of x in the numerator(as x is non zero);leaving (m-n) no. of x in the numerator, i.e. (x^m)/(x^n)=x^(m-n) now letting m=n,we have x^m/x^m=x^(m-m) or, 1=x^0 hence the proof if x is also 0,i.e. 0 to the power 0 is undefined!
InstructionTypeOpcodeSymbolicRepresentationDescriptionData transfer00001010000010010010000100000001000000100000001100000100LOAD MQLOAD MQ,M(X)STOR M(X)LOAD M(X)LOAD -M(X)LOAD |M(X)|LOAD -|M(X)|Transfer contents of register MQ to the accumulator ACTransfer contents of memory location X to MQTransfer contents of accumulator to memory location XTransfer M(X) to the accumulatorTransfer -M(X) to the accumulatorTransfer absolute value of M(X) to the accumulatorTransfer -|M(X)| to the accumulatorUnconditionalbranch0000110100001110JUMP M(X,0:19)JUMP M(X,20:39)Take next instruction from left half of M(X)Take next instruction from right half of M(X)Conditionalbranch0000111100010000JUMP+M(X,0:19)JUMP+M(X,20:39)If number in the accumulator is nonnegative, take next instruction from left half of M(X)If number in the accumulator is nonnegative , take next instruction from right half of M(X)Arithmetic0000010100000111000001100000100000001011000011000001010000010101ADD M(X)ADD |M(X)|SUB M(X)SUB |M(X)|MUL M(X)DIV M(X)LSHRSHAdd M(X) to AC; put the result in ACAdd |M(X)| to AC; put the result in ACSubtract M(X) from AC; put the result in ACSubtract |M(X)} from AC; put the remainder in ACMultiply M(X) by M(Q); put most significant bits of result in AC, put less significant bits in M(Q)Divide AC by M(X); put the quotient in MQ and the remainder in ACMultiply accumulator by 2 (i.e., shift left one bit position)Divide accumulator by 2 (i.e., shift right one bit position)Address modify0001001000010011STOR M(X,8:19)STOR M(X,28:39)Replace left address field at M(X) by 12 right-most bits of ACReplace right address field at M(X) by 12 right-most bits of AC
You do not have absolute deviation in isolation. Absolute deviation is usually defined around some measure of central tendency - usually the mean but it could be another measure. The absolute deviation of an observation x, about a measure m is |x - m| which is the non-negative value of (x - m). That is, |x - m| = x - m if x ≥ m and m - x if x < m
Well, isn't that just a happy little math question? When we say "m reduced by x," we are simply subtracting x from m. It's like taking away a few brushstrokes to reveal a new layer of the painting. Just remember, mistakes are just happy accidents waiting to be turned into something beautiful.
9 m x 2.5 m = 22.5 m2.
15 m x 1,000 m = 15,000 m2
1 in = 0.0254 m (exactly) ⇒ 70 in x 50 in = 70 x 0.0254 m x 50 x 0.0254 m = 1.778 m x 1.27 m