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How do you multiply two binomials?

Updated: 4/28/2022
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13y ago

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Apply the Distrubutive Property twice as you do when multiplying two-digit numbers Use the FOIL methed First Inner Outter Last. In the equation (3x + 4)(9x + 1) you get. (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 Now you multiply. 3x*9x = 27x^2 3x*1 + 9x*4 = 3x + 36x = 39x 1*4 = 4 So your entire answer is (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 = 27x^2 + 39x + 4

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Q: How do you multiply two binomials?
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Explain how I would use algebra times to multiply two binomials (FOIL)?


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It is only not needed if you know of another method. If FOIL is the only way you know to multiply two binomials, then it is definitely needed.


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Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.


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How do you multiply trinomials with binomials in algebra?

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If you multiply 2 binomials together will you always get a trinomial as a result?

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