2s - 12 + 2s = 4s - 124s - 12 = 4s - 124s = 4ss = s==========this is an identity and any number can be s
s = 7, t = -3
Presumably this is a simultaneous equation in the form of: 3r-4s = 0 2r+5s = 23 Multiply all the terms in the top equation by 2 and in the bottom equation by 3: 6r-8s = 0 6r+15s = 69 Subtract the bottom equation from the top equation: -23s = -69 Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number: s = 3 Substitute the value of s into the original equations to find the value of r: Therefore: r = 4 and s = 3
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
4 seasons in a year
9r2-4s2/9r+6sIt looks like you can factors the numerator(3r + 2s)(3r - 2s) [This is the factored form of 9r2-4s2]Put this back into the equation(3r+2s)(3r-2s)/9r+6sYou can also factor the denominator3(3r+2s)Put this back into the equation(3r+2s)(3r-2s)/3(3r+2s)You can cancel out the 3r+2s on top and bottom because they are the same they equal 1. Therefore your final answer is3r-2s over 3You could go further and say this is...r-(2/3)seither one is correct
Cant do much with this one.9r-4s / 9r+6s9r-4s / 3(3r+2s)
2s - 12 + 2s = 4s - 124s - 12 = 4s - 124s = 4ss = s==========this is an identity and any number can be s
2s + 16 = 4s - 6 Subtract 2s from both sides: 16 = 2s - 6 Add 6 to both sides: 22 = 2s divide both sides by 2: s = 11
1s 2s 3s 3p 4s 3d 4p
It is a simple linear equation in 's'. Its solution is the number that 's' must bein order to make it a true statement. The solution may be found like this:4s + 10 = 2s + 2Subtract 10 from each side of the equation:4s = 2s - 8Subtract 2s from each side:2s = -8Divide each side by 2 :s = -4
sucrose (C12H22O11 sucrose or glucose)
Daidzein is 7-Hydroxy-3-(4-hydroxyphenyl) chromen-4-one.Daidzin is 3-(4-hydroxyphenyl)-7-[(2S,3R,4S,5S,6R)-3,4,5-trihydroxy-6-(hydroxymethyl)oxan-2-yl]oxychromen-4-one.
14s 2d 7 - 6s 4d 5 + 8s 2d 3/2s 2d = 14s 7 - 3s 2s 5 + 4s 3
Sodium chloride is NaCl.Sodium hyaluronate has a very long and complicate name:Sodium (2S,3S,4R,5R,6R)-3- [(2S,3R,4R,5S,6R)-3-acetamido-4-[(2R,3R,4S,5S,6S)-6-carboxy-3,4,5-trihydroxyoxan-2-yl]oxy-5-hydroxy-6-(hydroxymethyl)oxan-2-yl]oxy-6-[(2R,3R,4R,5S,6R)-3-acetamido-2,5-dihydroxy-6-(hydroxymethyl)oxan-4-yl]oxy-4,5-dihydroxyoxane-2-carboxylic acid.
This abbreviated name is sucrose - in the English language.But the official name after the IUPAC rules is very long and complicate:(2R,3R,4S,5S,6R)-2-[(2S,3S,4S,5R)-3,4-dihydroxy-2,5-bis(hydroxymethyl)oxolan-2-yl]oxy-6-(hydroxymethyl)oxane-3,4,5-triol.
The difference between the number of 2s and the number of 4s in a sum.