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What is c when 12-2c equals 2c?
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
What would the solution be if c-5d equals 2 and 2c plus d equals 4?
c - 5d = 2 2c + d = 4 Multiply eqn 1 by 2: 2c - 10d = 4 Subtract this from eqn 2: 0c + 11d = 0 which implies that d = 0 Then, by eqn 1, c = 2
What does 11d plus 43 equal?
11d + 43=
What is 11d equals 1 equals 5d plus 49?
Do you mean: 11d +1 = 5d+49? If so: 11d+1 = 5d+49 11d-5d = 49-1 6d = 48 d = 8
What is the variable of 5d plus 2c?
9/12
What the answer for 2c plus 3 equals 15?
2c + 3 = 15 Subtract 3 from both sides: 2c = 12 Divide both sides by 2: c = 6
Cx2 plus 12-4 equals 20 what is c?
2c+(12-4)=20 Simplify the expression in the parentheses first. 2c+8=20 Subtract 8 from both sides of the equation. 2c=12 Divide both sides of the equation by 2. c=6
What are the variables and numbers of 5d plus 2c?
9/12
8(c - 9) = 6(2c - 12) - 4c?
its hard sorry
Is 20 pt and 2c 12 qt?
There are 2 pints in a quart, so 12 quart is 24 pints
If three bags of jellybeans and two bags of chocolate chips are 24 cents and 4 bags of chocolates and two bags of jellybeans are also 24 cents how much is each bag?
Call the jellybeans J and the chocolate chip bags CNow we have two equations 3J + 2C = 242J + 4C = 24 Therefore 3J + 2C = 2J+4C ,and 1J=2C, so 4J = 24, J = 6¢ (price of jellybeans) , therefore C =3¢ (price of chocolate chips) Or we can do the usual algebra method of making two of the values the same and subtracting the two equations. Multiply the second equation by -0.5 3J + 2C = 24- 1J -2C = -12-----------------2J +0C = 12 J = 6 3(6) + 2C = 24 18 + 2C = 24 2C = 24 - 18 2C = 6 C = 3
What is the greatest common factor of 2c2 2c?
the greatest common factor of 2c squared times 2c is 2c
