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What else can I help you with?
What is c when 12-2c equals 2c?
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
What would the solution be if c-5d equals 2 and 2c plus d equals 4?
c - 5d = 2 2c + d = 4 Multiply eqn 1 by 2: 2c - 10d = 4 Subtract this from eqn 2: 0c + 11d = 0 which implies that d = 0 Then, by eqn 1, c = 2
What does 11d plus 43 equal?
11d + 43=
What is 11d equals 1 equals 5d plus 49?
Do you mean: 11d +1 = 5d+49? If so: 11d+1 = 5d+49 11d-5d = 49-1 6d = 48 d = 8
What is the variable of 5d plus 2c?
9/12
What the answer for 2c plus 3 equals 15?
2c + 3 = 15 Subtract 3 from both sides: 2c = 12 Divide both sides by 2: c = 6
Cx2 plus 12-4 equals 20 what is c?
2c+(12-4)=20 Simplify the expression in the parentheses first. 2c+8=20 Subtract 8 from both sides of the equation. 2c=12 Divide both sides of the equation by 2. c=6
What is 3c-7 2c-5?
To simplify the expression (3c - 7 + 2c - 5), first combine like terms. The (c) terms (3c) and (2c) add up to (5c), while the constant terms (-7) and (-5) combine to (-12). Therefore, the simplified expression is (5c - 12).
8(c - 9) = 6(2c - 12) - 4c?
its hard sorry
Is 20 pt and 2c 12 qt?
There are 2 pints in a quart, so 12 quart is 24 pints
What is the greatest common factor of 2c2 2c?
the greatest common factor of 2c squared times 2c is 2c
If three bags of jellybeans and two bags of chocolate chips are 24 cents and 4 bags of chocolates and two bags of jellybeans are also 24 cents how much is each bag?
Call the jellybeans J and the chocolate chip bags CNow we have two equations 3J + 2C = 242J + 4C = 24 Therefore 3J + 2C = 2J+4C ,and 1J=2C, so 4J = 24, J = 6¢ (price of jellybeans) , therefore C =3¢ (price of chocolate chips) Or we can do the usual algebra method of making two of the values the same and subtracting the two equations. Multiply the second equation by -0.5 3J + 2C = 24- 1J -2C = -12-----------------2J +0C = 12 J = 6 3(6) + 2C = 24 18 + 2C = 24 2C = 24 - 18 2C = 6 C = 3
