5
2c-10
143542make the variables X plus Y plus Zthe solution is X*Y,X*Z, then (X+Z)*Y flipped7*2=147*5=35(7+5)*2=24 flipped =421435425*3=155*2=10(5+2)*3=21...flipped =12151012
(5, 1)
x = 5
4c+1-5+2c = 6c-4.
24c2 + 96c + 90 = 6*(4c2 + 16c + 15) = 6*(2c + 3)*(2c + 5)
An equation where c = 5
-((3c - 4)(3c + 4)(2c - 5)(2c + 5))
That would be 10
It is:- 3c+5 = c+15 Subtact 5 and c from both sides: 2c = 10 Divide both sides by 2 to find the value of c: c = 5
It depends on the value of c. If c = 0 then 0-0+5 = 5 If c = 1 then 1-2+5 = 4 If c = 2 then 4-4+5 = 5 and so on.
5 plus 25 equals 60. Need to solve for 5 plus 25 equals ?: 2 plus 10 equals 24 is equivalent to 2 × (1 plus 5) equals 2 × (12); and 3 plus 15 equals 36 is equivalent to 3 ×(1 plus 5) equals 3 × (12); thus 5 plus 25 equals ? is equivalent to 5 × (1 plus 5) equals 5 × (12); thus ? = 5 × 12 = 60.
2c 2(5) 10 The answer is 10. You plug in the value of 5 for c. When the number and variable touch directly it implies multiplication.
20+40c is the answer.
8c2-26c+15 8c2-6c-20c+15 2c(4c-3)+5(-4c+3) (2c-5)(4c-3)
It equals 24.