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There is no "formula" to solve this kind of equation; you simply have to put get the desired variable on the left side, and everything else to the right side.
a = 3b - 2c
Switch around:
3b - 2c = a
To get rid of the "2c", add "2c" to each side:
3b = a + 2c
To get rid of the 3, divide both sides by 3:
b = (a + 2c) / 3.
Add your answer:
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What is the formula to solve for b a equals 2b plus c?
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
How do you transpose A equals half h times a plus b to solve for a formula is for a trapezium?
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
How do you solve for x when a plus x equals b?
x=b-a
Y equals b plus x plus x2?
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
What is the whole cube of a b c?
(a + b + c) 3 = a3 + b3+ c3+ 3a2b + 3a2c + 3ab2 + 3ac2 + 3b2c + 3bc2 + 6abc
What is the original formula to solve for b in this problem a equals 2bc plus b?
Not sure about the original formula, but one that works is b = a/(2c + 1)
A plus b plus c whole cube equals?
(a + b+ c)3 = a3 + b3 + c3 + 3a2b + 3ab2 + 3b2c + 3bc2 + 3c2a + 3ca2 + 6abc
What is the formula to solve for b a equals 2b plus c?
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
Which of these formulas is rewritten form the original formula to solve for b a equals 2b plus c?
b= 1/2 (a - c)
Which of these formulas is correctly rewritten from the original formula to solve for b a equals 3b - 2c?
1
How do you solve y equals mx plus b solve for b?
b = y - mx.
How do you Solve the formula y equals mx plus b for M?
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
How do you transpose A equals half h times a plus b to solve for a formula is for a trapezium?
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
A plus b equals 8 and a minus b equals 9?
Solve one of the formulas for A, then substitute that into the other formula to solve for B, then substitute the solution for B into one of the formulas to solve for A. Here is how: Givens: A+B=8 A-B=9 So: If A+B=8 then A=8-B Next, substitute this into the other formula... A-B=9 (8-B)-B=9 (-B) - B = 1 (-2B) = 1 B= (- 1/2) Next, substitute the solution for B into one of the formulas to solve for A.... A+B=8 A+ (-1/2) = 8 A = 8 and 1/2 So... B= (- 1/2) A = 8 and 1/2
Solve A equals bh for b?
b=Ah
What is the formula called a equals b b equals c therefore a?
That is not a formula, it is the transitive property of equality.
B equals 10 plus a solve for a?
Not enough information to solve
