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27 Books in the New Testament
What else can I help you with?
What value of t make the equation t 48 75 true?
If you mean: t+48 = 75 then the value of t is 27 because 27+48 = 75
What is the difference between algebra and linear algebra?
Linear Algebra is a special "subset" of algebra in which they only take care of the very basic linear transformations. There are many many transformations in Algebra, linear algebra only concentrate on the linear ones. We say a transformation T: A --> B is linear over field F if T(a + b) = T(a) + T(b) and kT(a) = T(ka) where a, b is in A, k is in F, T(a) and T(b) is in B. A, B are two vector spaces.
How do you factor t squared minu s t-1squared?
Use the formula a^2 - b^2 = (a -b)(a + b). So: t^2 - (t - 1)^2 = [t - (t -1)][t + (t -1)] Now you can work and simplify the given expression. =(t - t +1)(t + t -1) =(1)(2t -1) = 2t -1
What is B called in the matrix representation of a system of linear equations when written as AX equals B?
A = coefficient matrix (n x n) B = constant matrix (n x 1)
Prove that the Jacobi iteration method applying to Ax=b is convergent for any initial x (0), provided that A is strictly diagonally dominant?
Answer: The Jacobi iteration method is an iterative method used to solve a system of linear equations Ax = b. This method is based on the idea that an approximate solution can be obtained by iteratively solving each equation for one of its unknowns while the other unknowns are kept fixed. In order for the Jacobi iteration method to converge, we must prove that it is convergent for any initial x (0) provided that A is strictly diagonally dominant. Let A be an n-by-n matrix and b be a vector in Rn. We assume that A is strictly diagonally dominant. This means that the absolute value of each diagonal element of A is greater than the sum of the absolute values of the non-diagonal elements in the same row. This can be expressed mathematically as: |a_jj| > ∑ |a_ij| , where i ≠ j and i, j = 1,2, ..., n. Now, let x(0) be the initial vector in Rn. The Jacobi iteration method for solving Ax = b is given by: x_j^{k+1} = (b_j - ∑_{i=1,i≠j}^{n}a_ijx_i^k) / a_jj , where j = 1,2, ..., n. We can prove that the Jacobi iteration method is convergent for any initial x (0), provided that A is strictly diagonally dominant, by using the following theorem. Theorem: Let A be an n-by-n matrix and b be a vector in Rn. Assume that A is strictly diagonally dominant and let x(0) be the initial vector in Rn. Then, the Jacobi iteration method is convergent for any initial x (0). Proof: We will prove the theorem by using the Banach fixed point theorem. Let X be the set of all vectors x in Rn and define a mapping T : X → X as follows: T(x) = (b_1 - ∑{i=1,i≠1}^{n}a_1ix_i) / a_11 , (b_2 - ∑{i=1,i≠2}^{n}a_2ix_i) / a_22 , ... , (b_n - ∑_{i=1,i≠n}^{n}a_nix_i) / a_nn . We will prove that T is a contraction mapping. To do this, we need to show that there exists a constant c >= 0 such that for all x, y in X, we have ||T(x) - T(y)|| ≤ c||x - y|| , where ||.|| is the Euclidean norm. From the definition of T, we have T(x) - T(y) = (b_1 - ∑{i=1,i≠1}^{n}a_1ix_i) / a_11 - (b_1 - ∑{i=1,i≠1}^{n}a_1iy_i) / a_11 , (b_2 - ∑{i=1,i≠2}^{n}a_2ix_i) / a_22 - (b_2 - ∑{i=1,i≠2}^{n}a_2iy_i) / a_22 , ... , (b_n - ∑{i=1,i≠n}^{n}a_nix_i) / a_nn - (b_n - ∑{i=1,i≠n}^{n}a_niy_i) / a_nn . Now, we can use the triangle inequality to get ||T(x) - T(y)|| ≤ ∑{j=1}^{n} |(b_j - ∑{i=1,i≠j}^{n}a_jix_i) / a_jj - (b_j - ∑_{i=1,i≠j}^{n}a_jiy_i) / a_jj| . Using the definition of T and the fact that A is strictly diagonally dominant, we can further simplify this to ||T(x) - T(y)|| ≤ ∑{j=1}^{n} |a_jj(x_j - y_j)| / |a_jj| ≤ ∑{j=1}^{n} |a_jj||x_j - y_j| / |a_jj| ≤ ∑_{j=1}^{n} |x_j - y_j| = ||x - y|| . Thus, we have shown that ||T(x) - T(y)|| ≤ ||x - y||, which implies that T is a contraction mapping. Therefore, by the Banach fixed point theorem, the Jacobi iteration method is convergent for any initial x (0). This completes the proof.
27 B in the N T?
27 Books in the New Testament
27 b in n t?
27 Books in the New Testament
Write a program to print Armstrong in c?
void main() { int n,b=0,t; clrscr(); printf("Enter the no"); scanf("%d",&n); t=n; while(n>0) { a=n%10; b=b+a*a*a; n=n/10; } if(b==t) { printf("Armstrong no"); } else { printf("Not an Armstrong no"); } getch(); }
When was T. B. Ilangaratne born?
T. B. Ilangaratne was born on 1913-02-27.
How do you spell 'beautiful' in Portuguese?
L-I-N-D-O or B-O-N-I-T-O (masculine) L-I-N-D-A or B-O-N-I-T-A (feminine)
Can you unscramble the letters i n s a t i a b l e?
insatiable is a word(means cant get enuff)
Program to check whether the given number is an Armstrong number?
<html> <head> <Script Language="JavaScript"> var a,n,b=0,t; n=parseInt(window.prompt("enter n","0")); t=n; while(n>0) { a=n%10; b=b+a*a*a; n=n/10; } if(b==t) { document.writeln("Armstrong no"); } else { document.writeln("Not an Armstrong no"); } </script> </head> </html>
Function to find the transpose of a sparse matrix?
// transpose for the sparse matrix void main() { clrscr(); int a[10][10],b[10][10]; int m,n,p,q,t,col; int i,j; printf("enter the no of row and columns :\n"); scanf("%d %d",&m,&n); // assigning the value of matrix for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("a[%d][%d]= ",i,j); scanf("%d",&a[i][j]); } } printf("\n\n"); //displaying the matrix printf("\n\nThe matrix is :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("%d\t",a[i][j]); } printf("\n"); } t=0; printf("\n\nthe non zero value matrix are :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { // accepting only non zero value if(a[i][j]!=0) { t=t+1; b[t][1]=i; b[t][2]=j; b[t][3]=a[i][j]; } } } printf("a[0 %d %d %d\n",m,n,t); for(i=1;i<=t;i++) { printf("a[%d %d %d %d\n",i,b[i][1],b[i][2],b[i][3]); } a[0][1]=n; a[0][2]=m; a[0][3]=t; int s[10],u[10]; if(t>0) { for(i=1;i<=n;i++) { s[i]=0; } for(i=1;i<=t;i++) { s[b[i][2]]=s[b[i][2]]+1; } u[1]=1; for(i=2;i<=n;i++) { u[i]=u[i-1]+s[i-1]; } for(i=1;i<=t;i++) { j=u[b[i][2]]; a[j][1]=b[i][2]; a[j][2]=b[i][1]; a[j][3]=b[i][3]; u[b[i][2]]=j+1; } } printf("\n\n the fast transpose matrix \n\n"); printf("a[0 %d %d %d\n",n,m,t); for(i=1;i<=t;i++) { printf("a[%d %d %d %d\n",i,a[i][1],a[i][2],a[i][3]); } getch(); }
What word can be made with these letters t r a n s b a c t?
Transact, if you lose the "b."
What consonants are between?
b t w n
Q5 Write a program to implement a calculator to perform all the four basic arithmetic operations on integers?
#include <stdlib.h> #include <stdio.h> #include <conio.h> int sum(int, int); int sub(int, int); int mul(int, int); int div1(int, int); int main() { int a,b,d; int ch; printf("\t\tCalculator Implementation\n"); printf("\t\t~\n"); printf("\t\t 1: Add\n"); printf("\t\t 2: Sub\n"); printf("\t\t 3: Multiply\n"); printf("\t\t 4: Divide\n"); printf("\t\t 5: Exit\n\n\n"); printf("\t\t Enter the choice: "); scanf("%d", &ch); if(ch==5) exit(0); printf("\nEnter first number: "); scanf("%d", &a); printf("\nEnter Second number: "); scanf("%d", &b); printf("\na = %d; b = %d;\n", a, b); printf("==============\n\n"); switch(ch) { case 1 : d=sum(a,b); printf("Sum %d + %d = %d",a,b,d); break; case 2: d=sub(a,b); printf("Subtraction %d - %d = %d",a,b,d); break; case 3: d=mul(a,b); printf("Multiplication %d * %d = %d",a,b,d); break; case 4 : d=div1(a,b); printf("Division %d / %d = %d",a,b,d); break; default: printf("Invalid Choice!"); getch(); } getch(); return 0; } int sum(int a, int b) { return a + b; } int sub(int a, int b) { return a - b; } int mul(int a, int b) { return a * b; } int div1(int a, int b) { return a / b; }
Write a c program to merge two array?
#include <stdio.h> #include <conio.h> void main(){ int a[10],b[10],c[10],i,j,m,n,tmp,k; printf("\nEnter the size of the 1st array:"); scanf("%d",&m); printf("\nEnter the size of the 2nd array:"); scanf("%d",&n); printf("\nEnter the 1st array values:"); for(i=0;i<m;i++){ scanf("%d",&a[i]); } printf("\nEnter the 2nd array values:"); for(i=0;i<n;i++){ scanf("%d",&b[i]); } for(i=0;i<m;i++) { for(j=0;j<m-i;j++) { if(a[j]>a[j+1]) { tmp=a[j]; a[j]=a[j+1]; a[j+1]=tmp; } } } printf("\n\n Array in the ascending order is - \n"); for(i=0;i<m;i++) { printf("\t %d",a[i]); } for(i=0;i<n;i++) { for(j=0;j<n-i;j++) { if(b[j]>b[j+1]) { tmp=b[j]; b[j]=b[j+1]; b[j+1]=tmp; } } } printf("\n\n Array in the ascending order is - \n"); for(i=0;i<n;i++) { printf("\t %d",b[i]); } i=j=k=0; while(i<n&&j<m) { if(a[i]<b[j]) c[k++]=a[i++]; else if(a[i]>b[j]) c[k++]=b[j++]; else { c[k++]=b[j++]; i++; j++; } } if(i<n) { int t; for(t=0;t<n;t++) c[k++]=a[i++]; } if(j<m) { int t; for(t=0;t<m;t++) { c[k++]=b[j++]; } } printf("\nFinally sorted join array is:"); for(k=0;k<(m+n);k++) printf("\t\n %d ",c[k]); getch(); }
