Use the formula a^2 - b^2 = (a -b)(a + b). So: t^2 - (t - 1)^2 = [t - (t -1)][t + (t -1)] Now you can work and simplify the given expression. =(t - t +1)(t + t -1) =(1)(2t -1) = 2t -1
[5(s^2)(t^2)]/40st since it is multiplication you can separate the fraction; = (5/40)(s^2/s)(t^2/t) = (1/8)st or = st/8
Suppose the points are P = (r,s) and Q = (t,u) Then gradient of PQ = (u - s)/(t - r) = m, say. Let Z = (x,y) be any point on the line. Then gradient ZP also = m that is (y - s)/(x - r) = m Equating the two expressions for m, (y - s)/(x - r) = (u - s)/(t - r) or y - s = (x - r)*(u - s)/(t - r) y = (x - r)*(u - s)/(t - r) + s = x*m - r*m - s This is of the form y = mx + b, where m is as defined above and b = -r*m + s
When B is given a 40metre start then B runs 960m in T secs and A runs 1000m in T-19 secs. When B is given a 30 second start then B runs 1000m in t secs and A runs 960m in t - 30 secs. Assume that the speed of A (Va) and B (Vb) is constant in both situations. Then Vb = 960 ÷ T = 1000 ÷ t, and Va = 1000 ÷ (T - 19) = 960 ÷ (t - 30) So 960t = 1000T, and 1000t - 30000 = 960T - 18240. Then 40t = -40T + 11760, t = -T + 294. Substituting for t in 960t = 1000T gives : -960T + 282240 = 1000T : 1960T = 282240 : T = 144 B 's speed is 960 ÷ T = 960 ÷ 144 = 6.67 metres per second. Assuming the same constant speed to run 5000 metres then the time taken is 5000 ÷ 6.67 = 750 seconds
BASKETBALL = 10 letters B=2 A=2 S=1 K=1 E=1 T=1 L=2 Number of permutations = 10! /2!2!2! = 10x9x8x7x6x5x4x3x2 / 2x2x2 =3,628,800 / 8 =453,600
2 s means 2 times s and t b means t times b 2 seats on a tandem bicycle
Use the formula a^2 - b^2 = (a -b)(a + b). So: t^2 - (t - 1)^2 = [t - (t -1)][t + (t -1)] Now you can work and simplify the given expression. =(t - t +1)(t + t -1) =(1)(2t -1) = 2t -1
If the sides of the triangle are a, b and c and the length is d, then, area of triangular cross section t = sqrt[s*(s-a)*(s-b)*(s-c)] square units where s = (a+b+c)/2 and then total area = 2*t + (a+b+c)*d suare units = 2t + 2sd square units.
T S B Sally was born on 1924-03-18.
eqb constant k For a general EQN A+B=S+T the equilibrium constant can be defined by[1] k={S}{T}/{A}{B} {S} = MOLAR CONC. OF S{T} = MOLAR CONC. OF T{A} = MOLAR CONC. OF A{B} = MOLAR CONC. OF B
S-U-B-S-T-I-T-U-T-E :)
A set "A" is said to be a subset of "B" if all elements of set "A" are also elements of set "B".Set "A" is said to be a proper subset of set "B" if: * A is a subset of B, and * A is not identical to B In other words, set "B" would have at least one element that is not an element of set "A". Examples: {1, 2} is a subset of {1, 2}. It is not a proper subset. {1, 3} is a subset of {1, 2, 3}. It is also a proper subset.
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The proof of this theorem is by contradiction. Suppose for convex sets S and T there are elements a and b such that a and b both belong to S∩T, i.e., a belongs to S and T and b belongs to S and T and there is a point c on the straight line between a and b that does not belong to S∩T. This would mean that c does not belong to one of the sets S or T or both. For whichever set c does not belong to this is a contradiction of that set's convexity, contrary to assumption. Thus no such c and a and b can exist and hence S∩T is convex.
insatiable is a word(means cant get enuff)
Chowder - 2007 The B-L-T-'s The Trouble with Truffles 2-11 was released on: Poland: 15 April 2009 USA: 11 June 2009
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 2 words with the pattern B-B-S-T. That is, seven letter words with 1st letter B and 3rd letter B and 5th letter S and 7th letter T. In alphabetical order, they are: babysat babysit