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Suppose the points are P = (r,s) and Q = (t,u)

Then gradient of PQ = (u - s)/(t - r) = m, say.

Let Z = (x,y) be any point on the line. Then gradient ZP also = m

that is (y - s)/(x - r) = m

Equating the two expressions for m,

(y - s)/(x - r) = (u - s)/(t - r)

or y - s = (x - r)*(u - s)/(t - r)

y = (x - r)*(u - s)/(t - r) + s = x*m - r*m - s

This is of the form y = mx + b, where m is as defined above and b = -r*m + s

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Q: How do you convert 2 coordinate points into slope intercept form y equals mx plus b?
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