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How many sides in regular n-gon whose sum of interior angles is 1080?
sum of interior angles = (n-2)180=1080 1080/180=n-2 6=n-2 8=n
What is the sum of of the measure of angles in a 11gon?
The sum of the internal angles is 180*(11 - 2) = 180*9 = 1620 degrees. The sum of the external angles is 360 degrees - irrespective of the number of sides.
What is the sum of the interior angles of a regular polygon with 27 sides?
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. Here, n = 27, so the sum of the interior angles is (27-2)*180 = 25*180 = 4500 degrees.
How do you find the sum of the measure of interior angles?
(number of sides - 2)*180 = total sum of interior angles
What is the sum of all of the angles inside a polygon?
Here is the formula- (Number of sides -2) x180 degrees = angle sum. The sum of the interior angles inside of a polygon will be 180*(n-2) degrees, where n=number of sides of the polygon. Example: a triangle has 3 sides; therefore, the sum of the angles inside will be equal to 180*(3-2)=180*(1)=180 degrees.
