12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
24
24
Smallest prime factor = smallest prime number which can be divided into the given number with no remainder 82/2=41, both 2 and 41 are prime and 2 is the smallest.
We are looking for the lowest common multiple of 3, 4 & 5. This is 60 (3 * 20, 4 * 15 & 5 * 12). We add 2 to this so that the remainder will be 2 on division. Therefore the smallest integer that meets these requirements is 62.
119
12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
0.6667
103
24
273
24
The answer is 8.
7
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
0.6154
Six.