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68

68

68

68

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68

Q: When a certain two digit number is divided by 7 the remainder is 5 When it is divided by 9 the remainder is also 5 What is the smallest possible value of the number?

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12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.

24

24

Smallest prime factor = smallest prime number which can be divided into the given number with no remainder 82/2=41, both 2 and 41 are prime and 2 is the smallest.

We are looking for the lowest common multiple of 3, 4 & 5. This is 60 (3 * 20, 4 * 15 & 5 * 12). We add 2 to this so that the remainder will be 2 on division. Therefore the smallest integer that meets these requirements is 62.

Related questions

12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.

273

0.6667

24

103

24

The answer is 8.

62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.

0.6154

Six.

0.8

36 divided by 28 would be 1 remainder 8and44 divided by 32 would be 1 remainder 12