12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
24
Smallest prime factor = smallest prime number which can be divided into the given number with no remainder 82/2=41, both 2 and 41 are prime and 2 is the smallest.
We are looking for the lowest common multiple of 3, 4 & 5. This is 60 (3 * 20, 4 * 15 & 5 * 12). We add 2 to this so that the remainder will be 2 on division. Therefore the smallest integer that meets these requirements is 62.
71
12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
273
0.6667
24
103
The answer is 8.
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
Six.
0.8
36 divided by 28 would be 1 remainder 8and44 divided by 32 would be 1 remainder 12
221 is the smallest number which when divided by 24 36 and 54 gives a remainder of 5 each time
If it can be divided by another certain number, it doesn't have a remainder...That is just repeating the question, not helping.