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An equation of a nonlinear function and provide two inputs to evaluate?
y=x2+3 x1=1 x2=2 y(x1) = 1*1+3 = 4 y(x2) = 2*2+3 = 7 x2/x1 = 2, While y2/y1 = 7/4 !=2, and thus the function is nonlinear.
1- Find the slope of the line that contains 7 -8 and 47?
let (x1, y1) = (4, 7) and ( x2, y2) = ( 7, -8). Then, Slope = m = (y2 - y1)/(x2 - x1) m = (-8 - 7)/(7 - 4) m = -15/3
How do you find the midpoint of line segments with given endpoints are given 1 3 7 7?
Midpoint = (x1+x2)/2 and (y1+y2)/2 So the midpoint is (4, 5)
Find the slope of the line that passes through each pair of points. (5, 8) & (-3, 7?
To find the slope of the line passing through two points (x1, y1) and (x2, y2), you use the formula: slope = (y2 - y1) / (x2 - x1). In this case, the points are (5, 8) and (-3, 7). Plugging the values into the formula, we get slope = (7 - 8) / (-3 - 5) = -1 / -8 = 1/8. Therefore, the slope of the line passing through the points (5, 8) and (-3, 7) is 1/8.
What is x squared plus five x minus fourteen?
The answer is: X1 = 2 X2 = -7
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