y=x2+3 x1=1 x2=2 y(x1) = 1*1+3 = 4 y(x2) = 2*2+3 = 7 x2/x1 = 2, While y2/y1 = 7/4 !=2, and thus the function is nonlinear.
let (x1, y1) = (4, 7) and ( x2, y2) = ( 7, -8). Then, Slope = m = (y2 - y1)/(x2 - x1) m = (-8 - 7)/(7 - 4) m = -15/3
Midpoint = (x1+x2)/2 and (y1+y2)/2 So the midpoint is (4, 5)
To find the slope of the line passing through two points (x1, y1) and (x2, y2), you use the formula: slope = (y2 - y1) / (x2 - x1). In this case, the points are (5, 8) and (-3, 7). Plugging the values into the formula, we get slope = (7 - 8) / (-3 - 5) = -1 / -8 = 1/8. Therefore, the slope of the line passing through the points (5, 8) and (-3, 7) is 1/8.
The answer is: X1 = 2 X2 = -7
If the variables are x1 & x2 the solution is : 1) x1=x1+x2; 2) x2=x1-x2; 3) x1=x1-x2; EX: x1=1 , x2=6; 1) x1= 1+6 = 7 2) x2= 7-6 =1 3 x1=7-1 =6 ============================================
If you mean 4x-32x-4 = 0, the answer is x= -1/7
m*2x*8 + m*32x*7 = 16mx + 224mx = 240mx
y=x2+3 x1=1 x2=2 y(x1) = 1*1+3 = 4 y(x2) = 2*2+3 = 7 x2/x1 = 2, While y2/y1 = 7/4 !=2, and thus the function is nonlinear.
7/8x -4 = 10 Multiply all terms by 8x: 7 -32x = 80x Add 32x to both sides 7 = 112x Divide both sides by 112 to find the value of x: x = 7/112 = 1/16
15x + 32x - 28 = 47x - 28 = (√47x)2 - (√28)2 = (√47x)2 - (2√7)2 = (√47x - 2√7)(√47x + 2√7)
let (x1, y1) = (4, 7) and ( x2, y2) = ( 7, -8). Then, Slope = m = (y2 - y1)/(x2 - x1) m = (-8 - 7)/(7 - 4) m = -15/3
2x2+7/x1
(x - 5)(5x - 7)
Let (x1, y1) = (8, -2) and (x2, y2) = (1, 4).The slope, m = (x1 - x2)/(y1 - y2) = (8 - 1)/(-2 - 4) = 7/-6 = - 7/6.
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It is equivalent to: 32x^2 +88x +21