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3x3 17x2 15x 2x 5

Updated: 4/28/2022
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3*3 = 9 17*2 = 34 15*2*5 = 150

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Q: 3x3 17x2 15x 2x 5
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What is the solution to y-2x 5 and x-2y-15?

Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3


Factor 6x2 plus 11x-10?

6x2 + 11x - 10 = (6x2 + 15x) - (4x + 10) = 3x(2x + 5) - 2(2x + 5) = (3x - 2)(2x + 5). Note, first, that the three co-efficients of the original quadratic expression are 6, 11, and -10. We need two numbers whose sum is 11 and whose product is (6)(-10) = -60. These two numbers turn out to be 15 and -4. Thus, we replace the middle term, 11x with 15x - 4x and proceed with the factorisation in the usual way.


What is the answer to -2x y5?

-2x = y^5 or y^5 = -2x y = (-2x)^(1/5)


Solve by substitution method 15x-20y7 5y-3 10x?

15x - 20y = 7 5y - 3 = 10x Let's solve the second equation for y. 5y - 3 = 10x add 3 to both sides; 5y = 10x + 3 divide by 5 to both sides; y = 2x + 3/5 Substitute the expression 2x + 3/5 for y to the first equation. 15x - 20y = 7 15x - 20(2x + 3/5) = 7 multiply by 20 each term of the parentheses; 15x -40x - 60/5 = 7 - 25x - 12 = 7 add 12 to both sides; -25x = 19 multiply by -1 to both sides; 25x = -19 divide by 25 to both sides; x = -19/25 Substitute -19/25 for x to y = 2x + 3/5 y = 2x + 3/5 y = 2(-19/25) + 3/5 y = -38/25 + 3/5 multiply 3/5 by 5/5; y = -38/25 + 15/25 y =-23/25 The solution set is (-19/25, -23/25) Check: 1. 15 x - 20y = 7 15(-19/25) - 20(-23/25) = 7? -285/25 + 460/25 = 7 ? 175/25 = 7 ? 7 = 7 2. 5y - 3 = 10x 5(-23/25) - 3 = 10(-19/25) ? -115/25 - 3 = -190/25 ? -115/25 - 3(25/25) = -190/25 ? -115/25 - 75/25 = -190/25 ? -190/25 = -190 / 25 or, -38/5 = -38/5 The solution set is (1/5, 1)


How do you change 15x-y-45 into slope intercept?

5y = 15x -45 Divide by 5 y = 15x/5 -45/5 y = 3x -9 y = mx + b m= 3 6 = -9 The slope is 3 The y intercept is -9

Related questions

What is 15x-18 equals -2x-5?

Here is the answer with Steps: 15x - 18 = -2x - 5 15x = -2x + 13 17x = 13 x = 13/17 x ~ .764705882


What is the factorization of the trinomial below 2x2 15x 25?

If you mean: 2x2+15x+25 then it is (2x+5)(x+5)


What is the factorization of the trinomial 2x2 plus 15x plus 25?

2x2 + 15x + 25 = (2x + 5)(x + 5)


What is -6x plus -4 plus 15x plus -5 plus -2x simplified?

7x-9


How do you solve -15X equals -5 times 3X plus 2?

-15x=-5*3x+2 -15x=-15x+2 +15x +15x ----------------- 0=2


What is the value of x in the equation 6 over x plus 3 over 2x equals 5 over 2?

X=36/X + 3/2X = 5/2 (Multiply both sides by 2X to get x out of the denominator)2X(6/X + 3/2X = 5/2)12+3 = 5X (new equation)5X = 15X = 3


How do you find the roots of quadratic equations that are not ending in zero?

if you have 3*x^2 + 2 * x + 3 = 4, you can rewrite it to3*x^2 + 2 * x - 1 = 0edit:example:2x**2-15x-15=15+2x+x**2subtract away from one side2x**2-15x-15-x**2=15-2x+x**2-x**2x**2-15x-15=15-2xx**2-15x-15-15=15-2x-15x**2-15x-30=-2xx**2-15x-30+2x=-2x+2xx**2-13x-30=0Factor (long way):-mulitply first and third terms:1*-30=-30-factors of -30 that add up to second term:30=1*2*3*5-30=-1*30, 1*-30-30=-2*15, 2*-15-30=-3*10, 3*-10-30=-5*6, 5*-6-rewrite polynomial:x**2-13x-30=0x**2-15x+2x-30=0-factor sets of terms (ie first and second, third and fourth):x**2-15x+2x-30=0x(x-15)+2(x-15)=0-factor:x(x-15)+2(x-15)=0(x+2)(x-15)=0-determine roots:x+2=0x+2-2=0-2x=-2x-15=0x-15+15=0+15x=15Factor (short way):x**2-13x-30=0-because the first term is x**2 you can:1. Take third term and factor, choose factors that add up to second term:30=1*2*3*5-30=-1*30, 1*-30-30=-2*15, 2*-15-30=-3*10, 3*-10-30=-5*6, 5*-62. Place factors in (x+a)(x+b) where a and b are factors of the third term whose sum is the second term(x+2)(x-15)3. Determine roots:x+2=0x+2-2=0-2x=-2x-15=0x-15+15=0+15x=15


What is 3x 5x-5?

15x because 5 cant go into 15x look at it like this 5 is a bird and 15x is a bee birds and bees are not the same so you cant add them the answer is 15x-5 good luck


Can you divide out common terms that are added or subtracted in numerator and denominator of a rational expression?

No. Terms that are added in numerators and denominators CANNOT be divided out. Only terms that are multiplied can be divided out. For example: (2x-3)/(41x-11) Nothing can be divided out. (4x-8)/(30x-10) -> factor out a 2 -> 2(2x-4)/2(15x-5) Divide out the 2 because it is being multiplied so the fraction reads: (2x-4)/(15x-5)


What is the solution to y-2x 5 and x-2y-15?

Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3


Is (-4 2) a solution of 2x - 5y 10?

Assuming y=2x+5 and x=2y-15y=2x+5 (1)x=2y-15 (2)Substitute y=2x+5 into (2):x=2(2x+5)-15x=4x+10-150=3x+10-150=3x-55=3x5/3=x (x=5/3)Substitute x=5/3 into y=2x+5:y=2(5/3)+5y=10/3+5y=25/3x=5/3, y=25/3


What is the derivative of x to the fourth power -3x cubed plus 5x2 divided by x squared?

If you mean: f(x) = x4 - 3x3 + 5x2 / x2 then: f(x) = x4 - 3x3 + 5 ∴ f'(x) = 4x3 - 9x2 If you mean: f(x) = (x4 - 3x3 + 5x2) / x2 then: f(x) = x2 - 3x + 5 ∴ f'(x) = 2x - 3