3(6x2-7x-24) by dividing all the terms by 3
There can be no answer since there is no equation: only an expression. It is possible to factorise the expression as follows: 6x2 - 5x - 11 = 6x2 + 6x - 11x - 11 = 6x(x + 1) - 11(x + 1) = (x + 1)(6x - 11) Just to add, if you meant 6x2 - 5x - 11 = 0, then the above factorise would give you either (x+1) = 0, or (6x-11)=0, so x=-1 or 11/6
-15x=-5*3x+2 -15x=-15x+2 +15x +15x ----------------- 0=2
9+6x2=21
6x2-9x-6 is equal to 66.
Factorising 15x-27xy gives 3x (5 - 9y).Factorising is to express a number or expression as a product of factors.When factorising always look for common factors. To factorise (15x-27xy) look for the highest factor between the two terms (3x). 15x - 27y = 3x (5 - 9y)
3(6x2-7x-24) by dividing all the terms by 3
6x^2 + 5x + 1 = (3x +1) (2x + 1)
I think you mean 6x2-15x-21 2x2-5x-7 2x2-7x+2x-7 x(2x-7)+1(2x-7) (x+1)(2x-7)
There can be no answer since there is no equation: only an expression. It is possible to factorise the expression as follows: 6x2 - 5x - 11 = 6x2 + 6x - 11x - 11 = 6x(x + 1) - 11(x + 1) = (x + 1)(6x - 11) Just to add, if you meant 6x2 - 5x - 11 = 0, then the above factorise would give you either (x+1) = 0, or (6x-11)=0, so x=-1 or 11/6
Divide all terms by 3:- 2x2+5x-3 = (2x-1)(x+3) when factored
6x + 9x^3 = 3x*(2 + 3x^2)
6x2 + 11x - 10 = (6x2 + 15x) - (4x + 10) = 3x(2x + 5) - 2(2x + 5) = (3x - 2)(2x + 5). Note, first, that the three co-efficients of the original quadratic expression are 6, 11, and -10. We need two numbers whose sum is 11 and whose product is (6)(-10) = -60. These two numbers turn out to be 15 and -4. Thus, we replace the middle term, 11x with 15x - 4x and proceed with the factorisation in the usual way.
-15x=-5*3x+2 -15x=-15x+2 +15x +15x ----------------- 0=2
9+6x2=21
35x + 15x = 50x
15x-16x = -1