5=3x+2 3x+2-2=5-2 3x=3 ------ 3 x=1
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
x = 7 and 2/3
3x+2 = 5x so 2x = 2 and hence x = 2/2 = 1
1
3x^2-2y x=3 y=5 3(3)^2-2(5) 3(9)-10 27-10 17 3x^2-2y=17
-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5
4x + 17 = x + 2 4x - x = 2 - 17 3x = -15 x = -5
x = -3 y = -2
X= -2 ! Since the equation must equal zero - 17+3x must equal 11. The variable 3x HAS to equal -6... therefore x is equal to minus 2.
No is does not except for one particular value of x.Another Answer:-If: 2/3x+15 = 17Then: x = 1/3Check: 2/(3*1/3)+15 = 17
If: y = 3x+4 and y = 2-7x Then: 3x+4 = 2-7x So: 3x+7x = 2-4 => 10x = -2 => x = -1/5 By substitution: y = 17/5 Solution: x = -1/5 and y = 17/5
3x + 2 = 3x + 6 This is not possible.
3x + 2 = 0 3x = -2 x = -2/3
3x - 7 = 2 3x = 9 x = 3
3x+12 = 18 3x = 18-12 3x = 6 x = 2
1) 3x-17=0 3x=17 x=17/3 2) 3x-25=0 3x=25 x=25/3