If: y = 3x+4 and y = 2-7x
Then: 3x+4 = 2-7x
So: 3x+7x = 2-4 => 10x = -2 => x = -1/5
By substitution: y = 17/5
Solution: x = -1/5 and y = 17/5
Eqn (A): => 2x + 5y = 16 Eqn (B): => 5x + 2y = -2 5*Eqn (A) - 2*Eqn (B): 21y = 84 => y = 4 Substituting for y in Eqn (a): x = -2
Equations: 7x+4y = 9 and 2x+3y = 1 Multiply all terms in the 1st equation by 2 and all terms in the 2nd equation by 7 So: 14x+8y = 18 and 14x+21y = 7 Subtract the 1st equation from the 2nd equation: 13y = -11 => y = -11/13 By substituting y = -11/13 into any of the equations x = 23/13 Therefore the solutions are: x = 23/13 and y = -11/13
To solve ordinary differential equations (ODEs) using two-stage semi-implicit inverse Runge-Kutta schemes, you first discretize the time variable into small steps. In each time step, you compute intermediate stages that incorporate both explicit and implicit evaluations of the ODE, allowing for the treatment of stiff terms. Specifically, the scheme involves solving a system of equations derived from the implicit stages to update the solution at each time step. This method provides better stability properties for stiff problems compared to explicit methods.
If: x+y = 7 and x2+y2 = 25 Then: x = 7-y and so (7-y)2+y2 = 25 => 2y2-14y+24 = 0 Solving the quadratic equation: y = 4 and y = 3 By substitution points of intersection: (3, 4) and (4, 3)
The area of rectangle is : 13832.797999999999
Eqn (A): => 2x + 5y = 16 Eqn (B): => 5x + 2y = -2 5*Eqn (A) - 2*Eqn (B): 21y = 84 => y = 4 Substituting for y in Eqn (a): x = -2
1 If: 2x+5y = 16 and -5x-2y = 2 2 Then: 2*(2x+5y =16) and 5*(-5x-2y = 2) is equvalent to the above equations 3 Thus: 4x+10y = 32 and -25x-10y = 10 4 Adding both equations: -21x = 42 or x = -2 5 Solutions by substitution: x = -2 and y = 4
Points: (7, 5) Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (4, 1) Length of perpendicular line: 5
Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Both equations intersect at: (4, 1) Perpendicular distance: square root of (7-4)2+(5-1)2 = 5
Points: (4, -2) Equation: 2x-y-5 = 0 Perpendicular equation: x+2y = 0 Equations intersect at: (2, -1) Perpendicular distance is the square root of: (2-4)2+(-1--2)2 = 5 Distance = square root of 5
The three stages of osmosis are isotonic, hypotonic, and hypertonic. In an isotonic solution, there is no net movement of water molecules. In a hypotonic solution, water moves into the cell, causing it to swell. In a hypertonic solution, water moves out of the cell, leading to cell shrinkage.
Equations: 7x+4y = 9 and 2x+3y = 1 Multiply all terms in the 1st equation by 2 and all terms in the 2nd equation by 7 So: 14x+8y = 18 and 14x+21y = 7 Subtract the 1st equation from the 2nd equation: 13y = -11 => y = -11/13 By substituting y = -11/13 into any of the equations x = 23/13 Therefore the solutions are: x = 23/13 and y = -11/13
recogning a new problem confronting it finding a solution integrating a new perspective
This includes services that help smooth out obstacles in trial stages as well as final running of software solution.
The Final Solution started quite late into the Holocaust. The order for the planning of the Final Solution was only given in June of 1940. Three stages could be: planning, implementation and covering-up.
boycott, Nuremberg laws, kristallnacht, ghettos, camps, deportations, the final solution, liberation Please see the related question. There are many different ways of dividing the Holocaust into stages ...
Well, there are 5 stages on pop cutie. After stage 5 there is a fashion show showing all your designs. After the fashion show there are just extra levels for you to try out and complete! There just for you to have more fun and enjoy the game.