This would be a tesseract (a 4-dimensional hypercube) with a hypervolume of 16 quartic-inches. However, this is almost certainly not what you mean to ask. You need to reword your question.
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Each side has dimensions of 4 inches x 4 inches so each side has an area of 16 square inches. There are six sides to a cube so the overall surface area is 16 square inches x 6, which is 96 square inches.
To find the length of each side of the square, we need to divide the perimeter by 4 since a square has four equal sides. Therefore, if the perimeter is 24 inches, each side would be 24 inches divided by 4, which equals 6 inches. So, each side of the square would be 6 inches long.
52 square inches for each layer, minimum with no overlap anywhere.
area of circle is pi times diameter squared divided by 4 A = 3.14 x 12 x 12 /4 = 113 square inches
That would be 1/4 of the area of the entire circle. pi * r^2/4 (or πr2/4). Area of a circle = pi*62 = 113.0973355 or about 113 square inches, which, when divided by 4, gives you 28.25 square inches.