To express "7 times a number increased by 4" mathematically, you would write it as 7x + 4, where x represents the unknown number. This expression indicates that you multiply the number by 7 and then add 4 to the result. So, if the number is 5, the expression would be 7(5) + 4 = 35 + 4 = 39.
4 times a number added to 7 times the number equals 33
(-8,1)
4 [ 3 (x-6) ] = 12 4 [ 3x -18 ] = 12 12x - 72 = 12 12x = 84 x = 7
Let n be the number. Then what you're asking for is 6n+(n+7).
It is: 4 times (7+1) = 32
That number would be 3
It could be: (4*11.25)+7 = 52
To find 4 times the sum of y and 7, you first calculate the sum of y and 7, which is y + 7. Then, you multiply this sum by 4 to get the final result. Therefore, the expression for 4 times the sum of y and 7 is 4(y + 7), which simplifies to 4y + 28.
8(5+4)+7 = 79
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
that answer is 48.
28
the number is 11
If: 3x+7 = 19 Then: 3x = 19-7 And: 3x = 12 So: x = 12/3 = 4
in the equation 3+4=7, 3 and 4 are the addends. 7 is the sum.
4*4=16 sum of 1+6 is 7, difference is 5 so 16 is answer