x^3y = 2, y = 4 Substitute 4 for y: (x^3)(4) = 2 x^3 = 8 x = 2
[2/(3/4)]/6 = (2/1 x 4/3)/6 = (8/3)/(6/1) = 8/3 x 1/6 =8/18 = 4/9 ≈ 0.44
(2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 will have a remainder of 1 when divided by 2, 3, 4, 5, 6, 7, 8, or 9. (2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 = 362,881
-1
(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations
8 x (9 - 3) 4^2 (9 - 3) - 4^2 12-4^2 4 x 8 =32
4 x 2/3 = (4x2)/3= 8/3= 22/34 x 2/3 = 8/3
4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 166 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 248 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32
It is an open sentence. 3x = 3 x X 2y = 2 x Y, If 8 is the product then: x = 4 and y = 2. 3 x 4 = 12 2 x 2 = 4 12- 4 = 8
7 - 3 = 4 4 x 2 = 8 8 x 3 = 24
(2 3/4) x 3 = 11/4 x 3 = 33/4 = 8 1/4
The HCF of 144 and 192 is 48. The LCM is 576.
2 x 3 x 8 = 48 3 x 4 x 4 = 48 2 x 2 x 12 = 48
2 x 2 x 2 x 3 = 24 1 x 24 2 x 12 3 x 8 4 x 6 6 x 4 8 x 3 12 x 2 24 x 1
half of three quarters is 1/2 x 3/4 = 3/8.half of three quarters is 1/2 x 3/4 = 3/8.half of three quarters is 1/2 x 3/4 = 3/8.half of three quarters is 1/2 x 3/4 = 3/8.
x^3 + 8 = (x + 2)(x^2 - 2x + 4)
8