If: 4x+(-12) = 8 then 4x = 20 and x = 5
If: 3x+5 = 4x+1 Then: x = 4
10x-7=4x+5 +7 +7 10x=4x+12 -4x -4x 6x=12 /6 /6 x=2
(The original question was misphrased.) 4x-7 = 2x+5 resolves as 2x-7 = 5 2x = 12 x = 6
6x + 5
No.
x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1
6x - 12 + 4x + 5 = 06x + 4x = 12 - 510x = 7x = 7/10
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
X2 + 4X - 5 = 0 what two factor of - 5 add up to 4? (X - 1)(X + 5) ----------------- ( so, X = 1 and X = - 5 )
If: 4x+(-12) = 8 then 4x = 20 and x = 5
4x3 + 16x2 - 180x = 4x(x2 + 4x - 45) = 4x(x + 9)(x - 5)
(x + 3)(4x + 5)
If you have an equation of x2 plus x2, it is the same as saying 2 times x plus 2 times x. This can be written as 2x + 2x or x2 + x2. It is the same, then, as 4x. For example, if x equals 5: 2(5) + 2(5) = 10 + 10 = 20. 20 also equals 4(5).
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
Add 4 to both sides. To complete the square, take half the x coefficient into the bracket: (x + 4/2)2 = (x + 2)2 = x2 + 4x + 4 Comparing with the original, need to add 4 to both sides of x2 + 4x = 5: (x2 + 4x) + 4 = (5) + 4 ⇒ x2 + 4x + 4 = 9 ⇒ (x + 2)2 = 9
x = 2 and x = -5