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As a product of its prime factors: 24*3*13 = 624
To find two numbers that multiply to 624, we can start by finding the prime factorization of 624, which is 2^4 * 3 * 13. From this, we can see that the two numbers that multiply to 624 are 2^2 * 3 * 13 and 2^2, which simplifies to 12 and 52. Therefore, 12 times 52 equals 624.
To determine if 4908 is divisible by 3, we need to sum its digits. 4 + 9 + 0 + 8 = 21. Since 21 is divisible by 3 (21 ÷ 3 = 7), 4908 is also divisible by 3. Therefore, 4908 is divisible by 3.
Well, darling, the positive integers divisible by 2 are all the even numbers, and the ones divisible by 3 are those multiples of 3. So, to find the numbers divisible by either 2 or 3, you just need to combine these two sets. In other words, it's the set of all even numbers and multiples of 3. Voilà!
this # is divisible by 3, 5, and 9 :-) ;-P