Well, darling, the positive integers divisible by 2 are all the even numbers, and the ones divisible by 3 are those multiples of 3. So, to find the numbers divisible by either 2 or 3, you just need to combine these two sets. In other words, it's the set of all even numbers and multiples of 3. Voilà!
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A number is divisible by 2 if that number is an even number, which means it ends in 0, 2, 4, 6, or 8.
A number is divisible by 3 if the sum of its digits is evenly divisible by 3.
Here are some consecutive odd integers. All must follow this form: x+x+2+x+2=3x + 6 6 is divisible by 3. So is 3x. If you add two integers that are divisible by 3, it is still divisible by three. The question is not about odd integers, but consecutive integers. This should be x + x+1 + x+2 =3x+3 A bit simpler would be the three in a row : x-1, x, x+1 which add up to 3x which can be divided by 3.
When adding negative integers, you subtract. (2+-1=1) When subtracting negative integers, you add. (2--3=5)
That is false. This type of statement is only true for prime numbers, not for compound numbers such as 6. Counterexample: 2 x 3 = 6
No, Associative proporties are not true for all integers. The deffinition for integer (n) 1. one of the positive or negative numbers 1, 2, 3, act., or zero. Compare whole number.
A non-positive integer is any integer that is less than or equal to zero. This includes all negative integers (such as -1, -2, -3, etc.) as well as zero itself. In mathematical notation, non-positive integers are represented as { ..., -3, -2, -1, 0 }.