4
21-7y+3x-xy7(3-y)+x(3-y)
5x + 3 = 18 Subtract 3 from both sides: 5x = 15 Divide by 5: x = 3.
2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
y-intercept = 3y-intercept ; x = 07y + 3x - 21 = 07y + 3(0) -21 = 07y -21 = 07y = 217y/7 = 21/7y=3
7y + 18 = 39 Therefore, 7y = 39 - 18 = 21 y = 21/7 y = 3
39 - 7y = 18,-7y = 18 - 39-7y = -21-7y/-7 = -21/-7y = 3
-6y+3 = -7y+8 -6y+7y = 8-3 y = 5
3x + 7y = 3*x + 7*y = 3*6 + 7*4 = 18 + 28 = 46
4y + 3 = 7y - 18Add 18 to each side of the equation:4y + 21 = 7ySubtract 4y from each side:21 = 3yDivide each side by 3:7 = y
4
1 + 7y = 5x - 2 7y = 5x - 3 - 5x = - 7y - 3 x = 7/5y + 3/5 ---------------------
3
7y+3x-21 =0 7y = -3x+21 y = -3/7x+3 The y intercept is 3
y = -1 and x = -3
7y = 3y - 12 4y = -12 y = -3
The lines intersect at (3, 5)