If: 31 is the highest common factor of 155 and 217 Then: 155x+217y = 31 Divide all terms by 31: 5x+7y = 1 So: 5*1/10 + 7*1/14 = 1 because 1/2 + 1/2 = 1 Therefore the possible values of x and y are 1/10 and 1/14 respectively Check: (155*1/10)+(217*1/14) = 31
5m
The other factor is 1.
(a + 2b)(a + 2b)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
factor the trinomial 16x^2+24x+9
You can't factor it
That does not factor neatly.
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
Not factorable
1
No