y = -1 and x = -3
If you mean: x+7y = 39 and 3x-2y = 2 Then by substitution: x = 4 and y = 5
12y - 4 = 7y + 165y = 20y = 4
If: 3x-7y+4 = 0 then 3x-7y = -4 The intercepts are at: x is at (-4/3, 0) and y is at (0, 4/7) Distance of x from the origin: 4/3 Distance of y from the origin: 4/7 Area of the triangle: 1/2*4/3*4/7 = 8/21 square units
4(1-4x+7y)
4
T = 3x + 7y; x = 4; y = 6T = 3x + 7y (substitute 4 for x, and 6 for y)T = 3(4) + 7(6) = 12 + 42 = 54
x+7y=16 ---------------------------1 3x- 7y=4 ---------------------------2 ------------------------------------------------------------------------------------------------------------------ 1+2 x+7y=16 3x-7y=4 4x=20 x=5 substitute x = 5 in x+7y=16 (5)+7y=16 7y=11 y=11/7
y = -1 and x = -3
The ordered pair is (5, 4).
If you mean: x+7y = 39 and 3x-2y = 2 Then by substitution: x = 4 and y = 5
x = 5 and y = 4
12y - 4 = 7y + 165y = 20y = 4
If: 3x-7y+4 = 0 then 3x-7y = -4 The intercepts are at: x is at (-4/3, 0) and y is at (0, 4/7) Distance of x from the origin: 4/3 Distance of y from the origin: 4/7 Area of the triangle: 1/2*4/3*4/7 = 8/21 square units
4(1-4x+7y)
7y+ 8x + 4= 20 + 8x- 8x - 8x7y + 4 = 20- 4 - 47y=16/7 /7y= 2.28the /7 means divide by 7 :)
(2, -1)