3X^2 + 9X/3X factor out 3X 3X(X + 3)/3X 3X/3X = 1, so... X + 3 is the simplest form here
-4
9x
3x. 15x - 9x = 6x 9x - 6x = 3x 6x - 3x = 3x 3x - 3x = 0
Apply the Distrubutive Property twice as you do when multiplying two-digit numbers Use the FOIL methed First Inner Outter Last. In the equation (3x + 4)(9x + 1) you get. (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 Now you multiply. 3x*9x = 27x^2 3x*1 + 9x*4 = 3x + 36x = 39x 1*4 = 4 So your entire answer is (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 = 27x^2 + 39x + 4
Assuming you mean 3x - 2 = 9x - 5...3x - 2 = 9x - 53x + 3 = 9x3 = 6x0.5 = x
3X^2 + 9X/3X factor out 3X 3X(X + 3)/3X 3X/3X = 1, so... X + 3 is the simplest form here
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
3x2-9x-30 =3x2+6x-15x-30 =3x(x+2)-15(x+2) =(3x-15)(x+2) OR 3(x - 5)(x+2)
x=2
(x - 3x - 6) / 6 = (3x + 2) / 3 ∴3x - 9x - 18 = 18x + 12 ∴3x - 9x - 18x = 12 - 18 ∴-24x = -6 ∴ x = 1/4
Right, 3x-4x+9x-x1. 3x - x = 2x2. 9x-4x = 5x- 2x +5x = 7x
factor out a 3x 3x(x-3)=3x2-9x
8 - 3x = 9x - 10 +3x +3x______________8 = 12x - 10+10 +10______________18 = 12x__ ___12 123/2 = x, or x = 1.5
-3X+Y = 2 becomes Y = 2+3X -9X + 2Y =2 becomes -9X + 2(2+3X) =2, which we can now solve. -9X + 4 + 6X = 2 -3X = -2 X = 2/3 Going back to our original equation: Y = 2+3(2/3) Y = 4
x=6
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).