It is 5 miles per hour.
Since the distance downstream (with the current) equals the distance upstream (against the current), and if we: Let B stand for the speed (rate in mph) of the boat in still water, and using the formula rate X time = distance, the equation will be: (B+7) x 3 = (B-7) x 5 3B + 21 = 5B - 35 56 = 2B B = 28 mph Traveling downstream, the current will cause the boat to go faster so the 7 mph current is added to the boat's still water speed. Traveling upsteam the current slows or decreases the boat's rate so the current's speed is subtracted from the boat's still water speed.
35 mph
The answer is 2.4 km/h. Distance = Speed * Time. For the initial journey: d=4*6 =24 km He took the same path back thus the distance is the same. 24=10*speed Speed = 2.4 km/h
Her average speed is 1.6 miles per hour. Average speed is total distance covered by total time taken to do it. She swims 4 miles upstream, and at 1 mph, it takes 4 hours. She comes back downstream at 4 mph and so she covers the 4 miles in 1 hour. Her total mileage is 8 miles. It takes 4 + 1 hours or 5 hours to cover it. The 8 miles divided by 5 hours is 1 3/5 miles per hour, or 1.6 mph for an average speed.
317
Since the distance downstream (with the current) equals the distance upstream (against the current), and if we: Let B stand for the speed (rate in mph) of the boat in still water, and using the formula rate X time = distance, the equation will be: (B+7) x 3 = (B-7) x 5 3B + 21 = 5B - 35 56 = 2B B = 28 mph Traveling downstream, the current will cause the boat to go faster so the 7 mph current is added to the boat's still water speed. Traveling upsteam the current slows or decreases the boat's rate so the current's speed is subtracted from the boat's still water speed.
Boats speed = 24 miles per hour.Current speed = 4 miles per hour.
Velocity = Distance ÷ Time.The speed upstream = 300 ÷ 5 = 60kph.The speed downstream = 300 ÷ 2 = 150 kph.The speed upstream equals boat velocity(Vb) minus current velocity(Vc).The speed downstream equals boat velocity (Vb) pluscurrent velocity (Vc).Vb - Vc = 60Vb + Vc = 150 : Adding the two equations together gives :-2Vb = 210 : Vb = 105, therefore Vc = 45The rate of the boat in still water is 105 kph. The rate of the current is 45 kph.
The average speed downstream is 40 ÷ 4 = 10 mph. However, it would seem that insufficient information has been supplied to enable a satisfactory answer to this question to be provided.
If 4 hours return seven then 6 hours has return in 4 hours and 2 more hours will no return within 4 hours.
35 mph
35 mph
The speed of the boat is 36 km/h. Going upstream: 3h x 36km/h = 108 km, minus (6x3 =18 km) = 90 km Going downstream: 2h x 36km/h = 72 km, plus (6x2 =12 km) = 90 km
Whilst travelling downstream the boat travels at V + C mph where V is the speed of the boat in still water and C is the speed of the current. Whilst travelling upstream the speed is V - C mph. The downstream velocity = 24/2 = 12mph = V + C therefore C = 12 - V Velocity (speed) = Distance ÷ Time : therefore Distance = Velocity x Time. As the distance in either direction is the same then, 2(V+C) = 3(V-C) 2V + 2C = 3V - 3C V = 5C : substituting for C as C = 12-V V = 5(12 - V) = 60 - 5V 6V = 60 : V = 10 mph. Therefore, C = 12 - 10 = 2 mph The speed of the boat in still water is 10 mph and the speed of the current is 2 mph.
The current schedule (April 2011) takes 9 hours 30 minutes from Venice to JFK and 8 hours 55 minutes on the return journey.
To do this, you need to form equations using the information given. There are 2 variables here, the base speed of the rower with no current (x), and the speed of the current (y). Firstly, convert the distances and times given into average speeds. 20km/2 hours = 10km/h 4km/2 hours = 2km/h The actual speed = the base speed +- the current, depending on direction. So 10 = x + y 2 = x - y If we subtract these 2 equations to eliminate x, we get: 8 = 2y y = 4km/h
The duration of Return to Me is 1.92 hours.