A gift box in the shape of a rectangular prism measures 8 inches by 8 inches by 10 inches. What is the least amount of wrapping paper needed to wrap the gift box?

Answer 1

448 sq. in.

Answer 2

Well, honey, to wrap that rectangular prism, you gotta find the surface area. Add up the area of all six sides: 2(8x8) + 2(8x10) + 2(8x10) = 320 square inches. So, you'll need at least 320 square inches of wrapping paper to cover that bad boy.

Answer 3

To calculate the least amount of wrapping paper needed to cover the gift box, you need to find the surface area of the rectangular prism. The surface area of a rectangular prism is calculated by adding the areas of all six faces. In this case, the formula would be 2lw + 2lh + 2wh, where l = length, w = width, and h = height. Plugging in the dimensions (8, 8, and 10 inches) into the formula, we get 2(88) + 2(810) + 2(8*10) = 256 + 160 + 160 = 576 square inches. Therefore, at least 576 square inches of wrapping paper are needed to cover the gift box.

Answer 4

Oh, dude, let's break out the wrapping paper and do some math! So, to find the least amount of wrapping paper needed, you calculate the surface area of the box. The formula for surface area of a rectangular prism is 2lw + 2lh + 2wh. Plugging in the dimensions, you get 2(8x8) + 2(8x10) + 2(8x10), which simplifies to 320 square inches. So, you'll need at least 320 square inches of wrapping paper to cover that bad boy. Happy wrapping!

Answer 5

448

Answer 6

448 square inches.