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Linear equations can be written in the following form: y = mx + b where m = slope and b = y-intercept In this case we are given the slope (m=9) so: y = 9x + b We are also given a single point (0, -5). Because this point gives us a value of x and y that are on the line, we can substitute those values into our equation to get b. y = 9x + b and x = 0 and y = -5 -5 = 9(0) + b -5 = b Substitute this value back into our equation to get the equation of the line y = 9x - 5

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Q: A line whose slope equals 9 and passes through point zero and negative 5?
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