Linear equations can be written in the following form: y = mx + b where m = slope and b = y-intercept In this case we are given the slope (m=9) so: y = 9x + b We are also given a single point (0, -5). Because this point gives us a value of x and y that are on the line, we can substitute those values into our equation to get b. y = 9x + b and x = 0 and y = -5 -5 = 9(0) + b -5 = b Substitute this value back into our equation to get the equation of the line y = 9x - 5
y = (2/3 x) - 16
it equals 0.000010 because the negative means the decimal point moves 6 spaces to the left
Yes.
The line is vertical and so the slope is undefined.
"14" is not a point; you need two coordinates to specify a point.
It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.
[ x = 3 ] and [ x = -2 ] are two separate vertical lines on the graph.The first vertical line passes through the point [ x = 3 ] on the x-axis.The second vertical line passes through the point [ x = -2 ] on the x-axis.Both lines have infinite slope.Neither line has a y-intercept.The lines are parallel, and they never intersect.
So this would be a verticle line which passes through the point at -3.
If you mean a slope of -1 then it is: y = -x+5
y = -4x is a line with a slop of -4 and a y-intercept of 0 (it passes through the point (0,0).
This is an equation of a straight line: y = 3x + 12, which passes through the point (0,12) and has a slope of 3 {for every 1 unit increase in x, y increases by 3}
y = (2/3 x) - 16
If you mean a slope of -1 then it is: y = -x+5
2
The equation is x = -7.
-- a straight line -- the slope of the line is ' 1 ' -- the line passes through the point [y= -3] on the y-axis
sda