a constant y=x-3 dy/dx=0 a straight line
If: 24 = 6-x-3 Then: x = -21
3
x=0
3 - x = 8x = 3 - 8x = - 5
a constant y=x-3 dy/dx=0 a straight line
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
If: 24 = 6-x-3 Then: x = -21
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
3
x=0
3 - x = 8x = 3 - 8x = - 5
First of all, if 'x' is 3, then 'x' doesn't equal -3x+3 . You must mean y = -3x + 3.If x=3, then (-3x + 3) = -6 .The graph is the point (3, -6) .
if this is an x,y plot, it would be a vertical line at x = -3
If: x-y = 4 and x-3y = 4 Then by solving the simultaneous equations: x = 4 and y = 0 So the lines intersect at (4, 0) which will be a vertical straight line
x = 13
x=3