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Q: A parabola that opens upward

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Opening up, the vertex is a minimum.

when you have y=+/-x2 +whatever, the parabola opens up y=-(x2 +whatever), the parabola opens down x=+/-y2 +whatever, the parabola opens right x=-(y2 +whatever), the parabola opens left so, your answer is up

A parabola opening up has a minimum, while a parabola opening down has a maximum.

If the number in front of the x squared is negative, then the parabola will open upwards. The opposite occurs when the number is positive.

Finding the vertex of the parabola is important because it tells you where the bottom (or the top, for a parabola that 'opens' downward), and thus where you can begin graphing.

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If the value of the variable is negative then the parabola opens downwards and when the value of variable is positive the parabola opens upward.

maximum point :)

maximum point :)

If a is greater than zero then the parabola opens upward.

Opening up, the vertex is a minimum.

When you look at the parabola if it opens downwards then the parabola has a maximum value (because it is the highest point on the graph) if it opens upward then the parabola has a minimum value (because it's the lowest possible point on the graph)

It is a function because for every point on the horizontal axis, the parabola identified one and only one point in the vertical direction.

I think it's like this: x2+3x-5 So if the x2 part is a positive then it opens upward but if it's negative it goes downward.

positive.

when you have y=+/-x2 +whatever, the parabola opens up y=-(x2 +whatever), the parabola opens down x=+/-y2 +whatever, the parabola opens right x=-(y2 +whatever), the parabola opens left so, your answer is up

The standard equation for a Parabola with is vertex at the origin (0,0) is, x2 = 4cy if the parabola opens vertically upwards/downwards, or y2 = 4cx when the parabola opens sideways. As the focus is at (0,6) then the focus is vertically above the vertex and we have an upward opening parabola. Note that c is the distance from the vertex to the focus and in this case has a value of 6 (a positive number). The equation is thus, x2 = 4*6y = 24y

Vertex

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