The maximum.
Vertex
It is (y - b)^2 = ax + c
First you need more details about the parabola. Then - if the parabola opens upward - you can assume that the lowest point of the triangle is at the vertex; write an equation for each of the lines in the equilateral triangle. These lines will slope upwards (or downwards) at an angle of 60°; you must convert that to a slope (using the tangent function). Once you have the equation of the lines and the parabola, solve them simultaneously to check at what points they cross. Finally you can use the Pythagorean Theorem to calculate the length.
The vertex is not affected by the direction that the parabola is facing. The vertex is the place where the two sides of the parabola meet. It is in the middle divides the shape in half. If you picture yourself looking at a bowl from the side and then imagining it as two dimensional, it would look like a parabola but for all of the filled in parts of the graph and the fact that the sides of the bowl don't continue on forever. The vertex is the bottom of the bowl, where the sides meet. You measure a vertex as you would a point; with a coordinate.
maximum point :)
Opening up, the vertex is a minimum.
The maximum.
The maximum point.
A parabola that opens upward is a U-shaped curve where the vertex is the lowest point on the graph. It can be represented by the general equation y = ax^2 + bx + c, where a is a positive number. The axis of symmetry is a vertical line passing through the vertex, and the parabola is symmetric with respect to this line. The focus of the parabola lies on the axis of symmetry and is equidistant from the vertex and the directrix, which is a horizontal line parallel to the x-axis.
The standard equation for a Parabola with is vertex at the origin (0,0) is, x2 = 4cy if the parabola opens vertically upwards/downwards, or y2 = 4cx when the parabola opens sideways. As the focus is at (0,6) then the focus is vertically above the vertex and we have an upward opening parabola. Note that c is the distance from the vertex to the focus and in this case has a value of 6 (a positive number). The equation is thus, x2 = 4*6y = 24y
Vertex
If the value of the variable is negative then the parabola opens downwards and when the value of variable is positive the parabola opens upward.
Finding the vertex of the parabola is important because it tells you where the bottom (or the top, for a parabola that 'opens' downward), and thus where you can begin graphing.
If a is greater than zero then the parabola opens upward.
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
It is (y - b)^2 = ax + c