distance = 1/2 circumference
displacement = 2 r (special case because exactly half of the circle was travelled)
circumference = 2*pi*r
1/2 circumference = 1/2*2*pi*r = pi * r
Time in Distance 1+ time in distance 2= 22let the 1st Distance be x2nd Distance = 500-xtime = distance / speedx/10 + (500-x)/50= 22LCM = 50multiply equation by 505x+500-x=11004x=600x=150 m150 m at 10m/s350 m at 50m/s
None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.
T = Distance/R
weight x distance = work
14
The displacement of a satellite when it completes one round along its circular path is zero. This is because the displacement is the shortest distance between the starting and ending points, and in a circular path, the starting and ending points are the same.
The distance traveled by the body when it completes half a revolution along a circular path of radius R is equal to the circumference of half the circle, which is πR. The displacement of the body would be zero as it returns to the same starting point after completing half a revolution.
Distance covered - 2199m Displacement - 200m Distance covered - 2199m Displacement - 200m
double of the radius means equal to diameter
The distance traveled by the boy would be the circumference of the circle, which is calculated using the formula: Circumference = 2πr, where r is the radius of the circle. When the boy completes one round on the circular track, he travels a distance equal to the circumference of the circle.
the distance around a circular region is called circumference
Circular diameter is the distance from side to side of a circle through the middle.
Time=2m and 20 seconds ( converts it into second) s0 time in seconds = 140 seconds now v=w*r = 2*22/7*100 40 seconds = 2 * 22/7 *100 1 second = 2 * 22/7 * 100/40 140 second = 2 * 22/7 * 100/40 * 400 so, it gives = 2200 m so the distnace is 2200 m and the dispalcement is 200 m
Diameter.
Sure. As one car goes around a circle and as it completes one full rotation, then distance covered by the car is the circumference of the circle. But the displacement is Zero. So distance but no displacement.
The perpendicular distance between its circular ends
Yes, if it is a circular track.