Consider the pentagon ABCDE. By drawing diagonals from B, we get: 1. Triangle ABE 2. Triangle BDE 3. Triangle BCD -Ashwin Hendre
A regular hexagon can be divided into 6 equilateral triangles by drawing diagonals between opposite vertices, if that helps.
You Can Get 6 triangles
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
Number of sides minus 2 equals the number of triangles within the polygon.
There are 8
depends on what shape that vertex is in