Consider the pentagon ABCDE.
By drawing diagonals from B,
we get:
1. Triangle ABE
2. Triangle BDE
3. Triangle BCD
-Ashwin Hendre
A hexagon can be divided into four triangles by drawing all of the diagonals from one vertex. Since a hexagon has six sides, drawing diagonals from one vertex creates three additional triangles, resulting in a total of four triangles (the original triangle formed by the vertex and two adjacent vertices, plus the three formed by the diagonals).
4
There are 8
5 triangles.
A polygon with ( n ) sides can be divided into ( n - 2 ) triangles by drawing all the diagonals from one vertex. This is because each diagonal connects the chosen vertex to another vertex, forming a triangle with each adjacent pair of vertices. Therefore, for a polygon with ( n ) sides, you will create ( n - 2 ) triangles in total.
3 triangles
Three triangles
A hexagon can be divided into four triangles by drawing all of the diagonals from one vertex. Since a hexagon has six sides, drawing diagonals from one vertex creates three additional triangles, resulting in a total of four triangles (the original triangle formed by the vertex and two adjacent vertices, plus the three formed by the diagonals).
depends on what shape that vertex is in
1 triangle is formed.
You Can Get 6 triangles
4
There are 8
5 triangles.
21
A heptagon has seven sides, so when drawing diagonals from one vertex, it will create five triangles. This is because each diagonal drawn from a single vertex will create a triangle until it intersects the previous diagonal. Therefore, the number of triangles formed by drawing all diagonals from one vertex in a heptagon is five.
A polygon with ( n ) sides can be divided into ( n - 2 ) triangles by drawing all the diagonals from one vertex. This is because each diagonal connects the chosen vertex to another vertex, forming a triangle with each adjacent pair of vertices. Therefore, for a polygon with ( n ) sides, you will create ( n - 2 ) triangles in total.