You Can Get 6 triangles
3 triangles
33 triangles
A hexagon has 9 diagonals. Each vertex of a n-sided polygon can be connected to n - 3 others with diagonals. Thus n(n - 3) possible diagonals. However, when Vertex A is connected to vertex C, vertex C is also connected to vertex A, thus each diagonal is counted twice. Thus: number_of_diagonals = n(n - 3)/2 = 6(6-3)/2 = 6x3/2 = 9
There can be 14 lines in a seven side shape * * * * * That is the total number of diagonals from ALL vertices. Not what the question asked, though. From one vertex, there can be 4. One to every other vertex except for itself and one each on either side.
Find the midpoint of the two diagonals
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
5 triangles are formed.
depends on what shape that vertex is in
As many as she wants.
3 triangles
Three triangles
4
There are 8
5 triangles.
21
A heptagon has seven sides, so when drawing diagonals from one vertex, it will create five triangles. This is because each diagonal drawn from a single vertex will create a triangle until it intersects the previous diagonal. Therefore, the number of triangles formed by drawing all diagonals from one vertex in a heptagon is five.
6 triangles because there are 180 degrees in a triangle and 6*180 = 1080 degrees which is the sum of the angles in octagon when added up.