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What is the velocity of a plane that traveled 3000 miles from New York to California in 5 hours?
Its average speed is (3000/5) = 600 miles per hour.
What is plane in algebra?
A plane is the coordinate plane.
The intersection of a plane and a line is?
If the line is not IN the plane ... it just zaps through the plane from some direction ... then it touches the plane in only one point. The intersection is a point.if it is lined up with the plane, then the intersection is a line.
The intersection of plane KQU and plane XEP is?
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What is the other name for the Cartesian plane?
The coordinate plane
How far does a plane fly in 15 seconds while it's velocity is increasing from 75 m s to 145 m s at a uniform rate of acceleration?
To calculate the distance traveled while the velocity is increasing, you can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. In this case, the initial velocity is 75 m/s, the final velocity is 145 m/s, the acceleration is constant, and the time is 15 seconds. Plugging these values into the formula will give you the distance the plane travels during the acceleration period.
How far does a plane fly in 15 seconds while its velocity is increasing from 75 miles per second to 145 miles per second at a uniform rate of acceleration?
To find the distance traveled, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. The initial velocity is 75 miles per second, the final velocity is 145 miles per second, and the time is 15 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time. Plug in the values to find the acceleration and then calculate the distance traveled in 15 seconds.
How far does a plane fly in 15 seconds while its velocity is increasing from 75 ms to 145 ms at a uniform rate of acceleration?
To find the distance the plane travels, you can use the average velocity formula, which is the sum of initial velocity and final velocity divided by 2, and then multiply by the time. Average velocity = (75 m/s + 145 m/s) / 2 = 110 m/s Distance traveled = (110 m/s) * 15 s = 1650 meters
A plane traveling at 80 ms lands on a runway and comes to rest after 10 seconds What was the plane's deceleration?
The plane's deceleration can be calculated using the equation: acceleration = change in velocity / time taken. The plane's initial velocity is 80 m/s, final velocity is 0 m/s, and time taken is 10 seconds. Therefore, the deceleration is 8 m/s^2.
If a crate weighing 508 N is resting on a plane inclined 26degrees above the horizontal if acceleration is 4.29 then how fast will the crate be moving after 6 seconds?
To determine the speed of the crate after 6 seconds, we first need to calculate the net force acting on the crate on the inclined plane. This can be done by resolving the weight of the crate into components parallel and perpendicular to the plane. Then, using Newton's second law, F = ma, where F is the net force, m is the mass of the crate, and a is the acceleration, we can find the acceleration down the incline. After finding this acceleration, we can use the kinematic equation v = u + at to calculate the final speed of the crate after 6 seconds, where v is the final velocity, u is the initial velocity (assumed to be 0), a is the acceleration, and t is the time.
A plane traveling at 80 ms lands on a runway and comes to rest after 10 seconds what was the distance it traveled down the runway before it stopped?
The distance the plane traveled before stopping can be calculated by using the formula: distance = initial velocity * time + (1/2) * acceleration * time^2. Given initial velocity 80 m/s and time 10 seconds, and assuming acceleration is 0 m/s^2 (since the plane comes to rest), the distance traveled would be 800 meters.
If a planes initial speed is 0 meters per second and is accelerated at 15 meters per second squared what is its speed for 0-10?
The plane's velocity at 10 seconds will be 150 meters per second or 335.54 mph
How fardoes a plane fly in 15 seconds while its velocity is increasing from 75ms to 145ms at a uniform rate of acceleration?
Well, first you solve for acceleration using "a= (Vf-Vi)/t" a= (Vf-Vi)/t a=(145-75)/15 a=70/15 a=14/3 m/s2 Then you can use "d=vit+1/2at2" to solve for distance d=vit+1/2at2 d=(75)(15)+1/2(14/3)(15)2 d=1125 + 525 d=1650m And there's your answer. ---- Alternatively, you could use d=t(vi+vf)/2 d=t(vi+vf)/2 d=15(75+145)/2 d=1650m
What is the skydivers velocity after two seconds?
We'll assume you mean 2 seconds AFTER he's jumped from the plane. A good estimate would be 9.8m/s times 2 (9.8m/s/s times 2 seconds -- the standard value of the acceleration due to gravity). In two seconds, the velocity would be low enough that air resistance could probably be ignored for purposes of answering your homework. So try 19.6 m/s, unless your teacher gave your data on the air resistance of the sky diver.
What is a rough estimate of the average terminal velocity of a cargo plane assuming only acceleration due to gravity?
Assuming that it's flown well, the terminal velocity is just about the stall speed of the aircraft - between 80 and 150 mph. If it's just falling out of the sky then it may exceed mach (aprox 750 mph).
What is an acceleration of negative 20 meters per second squared?
A negative acceleration has the affect of decreasing the velocity of the moving object.If a plane is climbing at a speed of 100 meters per second and is subject to an acceleration of -20 meters per sec2 then after 1 second it's climbing speed will reduce to 80 mps, after 2 seconds to 60 mps .....and so on.This is illustrated by the law of motion v = u + ft, where u is the initial velocity, v is the final velocity, f is the acceleration and t is the time.How long does it take the plane to reach a zero climbing velocity.v = u + ft : 0 = 100 -20t : 20t = 100 : t = 5 seconds, which can be easily verified from the example a few lines above.
How far does a plane fly in 15 seconds while its velocity is increasing?
Not enough information is given.
