Pythagoras! Two sides of the triangle must each be equal to the radius, ie 3 so Hypotenuse = sqrt(3^2 + 3^2) =sqrt 18 = 4.243
Use the hypotenus theorem. the side opposite the right angle squared is equal to each of the other 2 sides squared and then added together
An isosceles triangle is a triangle that has two sides of equal length.
Depends on what shape you're looking to find the area of.Area of a rectangle = Length x Width x Height(same for parallelogram)Area of a triangle = 1/2 Base x Height or S^2 times root four divided by threeCircumference of a circle = 22/7 (of 3.14) x the diameter of the circle. A Square or Rectangle: Multiply the length of the rectangle by the width of the rectangle or the opposite. A Triangle: Multiply the the Base length (from the bottom of triangle to the tip on top) by the Width of the triangle. Then, divide your results in half. A Circle: Multiply the radius by radius by 3.14 (pi) to find answer.
An isoceles triangle has 2 sides of equal length
False
2
Short leg = x Long leg = x times the square root of 3 Hypotenuse = 2x
Use the hypotenus theorem. the side opposite the right angle squared is equal to each of the other 2 sides squared and then added together
Yes. It follows from one of the circle theorems which states that the angle subtended in a semicircle is a right angle.
The length of the circle's diameter
This is true. The answer is obvious if you think about it the following way: an equilateral triangle has three equal sides, and every point on the circumference of a circle is the same distance from the center of the circle. Therefore, it is safe to assume that the circle will touch the midpoint of each side of the triangle. It also means that the center of the circle will be in the center of the triangle. Therefore, the radius of the circle will travel from the center of the triangle to the midpoint of one of the sides. This will cover the distance of half the triangle's median.
You use the information you're given, combined with all of the equations, formulas,and relationships you know concerning the parts of a right triangle, to find the itemof information that you don't know yet. So the process you follow depends on theinformation you're given.For example, if you're given the lengths of the two legs of the triangle, and you'retold that the triangle is a right triangle, then you use the Pythagorean equationC2 = A2 + B2to find the length of the hypotenuse.
To construct a right triangle given the radius of the circumscribed circle and the length of a leg, begin with two ideas. First, the diameter of the circle is equal to twice the radius. That's pretty easy. Second, the diameter of the circle is the length of the hypotenuse. The latter is a key to construction. Draw your circle, and draw in a diameter, which is the hypotenuse of the right triangle, as was stated. Now set you compass for the length of the leg of the triangle. With this set, place the point of the compass on one end of the diameter (the hypotenuse of your triangle), and draw an arc through the circumference of the circle. The point on the curve of the circle where the arc intersects it will be a vertex of your right triangle. All that remains is to add the two legs or sides of the triangle. Draw in line segments from each end of the hypotenuse (that diameter) to the point where your arc intersected the curve of the circle. You've constructed your right triangle. Note that any pair of lines that is drawn from the ends of the diameter of a circle to a point on the curve of the circle will create a right triangle.
With a right triangle you can use the Pythagorean formula. a^2 + b^2 = c^2 We will call the hypotenuse c and the leg a 15^2 + b^2 = 39^2 ( rearrange ) b = sqrt of 39^2 - 15^2 = 36
If the sides of the triangle are equal in length to the radius of the circle, then you can simply place the two ends of the hypotenuse on the perimeter of the circle, and it's remaining corner will lie at the circle's center.
The area of a circle is equal to that of a triangle whose base has the length of the circle's circumference (distance around the circle) and whose height equals the circle's radius which comes to Pi multiplied by the radius squared. Area of Triangle 1/2 *base*height
The diameter of the circle will also be the triangle's hypotenuse so use Pythagoras theorem to find the hypotenuse's length and half the length which will result as a radius of 5 cm.