I assume you are referring to the sine function of mathematics. That function is defined as the ratio of the length of the side of a right triangle opposite the angle Theta to the length of the hypotenus. When the right triangle is taken to its extreme where the opposite side is the same as the hypotenus, that is the hypotenus and the opposite side are coincident and equal, then the sine function is at its maximum value of 1 (the angle Theta is 90 degrees). When the angle Theta is negative 90 degrees, or 270 degrees, the opposite side is coincident with the hypotenus but directed down, the ratio of lengths is then -1, the minimum value of the sine of Theta.
Theata = Tan^-1(Ay/Ax) Theata = 75.7 deg
= 1/sqrt(2) = 0.7071
In radians; -0.8939966636 In degrees; -1, of course
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
1
the value of sin(x) lies between -1 to +1. the approx value of sin(x)/x = 1 when x tends to 0 & sin(x)/x = 0 when x tends to infinity.
Theata = Tan^-1(Ay/Ax) Theata = 75.7 deg
Sin(x) has a maximum value of +1 and a minimum value of -1.
If you know that "sin(x)sin(x)=1", this must mean that just sin(x)=1 or -1, since sin(x) can take any value between -1 and 1, but both must be the same in order for "1" to be the product.Now, plot a regular sin(x) curve, and find all the possible points where sin(x)= 1 or -1. These are your x values.
It is: sin(90) = 1
sin(3π/2) = -1
1.570796327
The sine function (sin x) can only have values in the range between 1 and -1. Perhaps you can work it out from there.
x = sin-1 (4/15) ( sin -1 is [SHIFT] [sin] on a calculator ) = 15.5
= 1/sqrt(2) = 0.7071
In radians; -0.8939966636 In degrees; -1, of course
The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]