12
The sum of the cubes of the first 100 whole numbers is 25,502,500.
This is a cracking question. [I'm assuming that 'integral side lengths' is intended also to mean integral positions. That is to say, the position vectors of the cubes' vertices should consist only of integer components...such that we are effectively drawing our cube in a 3D grid. If this was not a condition, the answer would be infinity.] So then: first, there are 53 = 125 1x1x1 cubes. Then 43 = 64 2x2x2cubes. 33 = 27 3x3x3 cubes. 23 = 8 4x4x4 cubes. And, stunningly, 13 = 1 5x5x5 cube. So far we have 225 cubes. That would not be interesting. But we have only counted the cubes with edges parallel to the edges of the main cube. Suppose there are some more cubes formed by diagonal lines? Since edge lengths and vertex positions both have to be integral, and we are working in 3 dimensions, we are actually looking for Pythagorean quadruples - integer solutions to a2 + b2 + c2 = d2 Up to now we have only used trivial solutions like this: 52 + 02 + 02 = 52 Our edges have only moved in one dimension. We might consider edges that move in two dimensions, using the smallest Pythagorean triple: 32 + 42 + 02 = 52 But diagonal edges of length five are clearly not going to fit. So introduce the third component, and we find this: 12 + 22 + 22 = 32 By using diagonal edges it is possible to constuct a few more valid 3x3x3 cubes. It turns out, I think, that four of these can be formed. So we have 229 cubes in total.
In the case of a rectangular cuboid, I would say that the volume is simply DEFINED to be length x width x height. The volume of other, more complicated shapes, can then be derived, based on this basic definition. But you do need to have a starting point, i.e., "How is volume even defined in the first place?"Just to show that this definition makes sense, think of a rectangular cuboid as having integer values for length, width, and height. In that case, you can divide it into unit cubes (cubes of side length 1), and it is easy to see (basically, by counting the unit cubes) that the number of unit cubes will be length x width x height - IN THIS SPECIAL CASE.
The ratios of areas are the squares of the ratio of lengths (and the ratio of volumes are cubes of the ratio of lengths). As the perimeter of the second is twice the perimeter of the first, each length of the second is twice the length of the first, and so the ratio of the lengths is 1:2 Thus the ratio of the areas is 1²:2² = 1:4. Therefore the surface area of the larger prism is four times that of the smaller prism.
Those conditions satisfy the conditions of a function.
1,8,27.64.125, 216 and 343 are the first seven cubes.
The sum of the cubes of the first 100 whole numbers is 25,502,500.
what is the answer and how did you get it
Scenery was first painted during the Renaissance.
If you have one cube in the first solid than six cubes in the second solid and than fifteen cubes in the third solid, than you would get 215 cubes in the eighth solid.
Boil it first
8.33
The first represents a smaller value (but is not necessarily smaller). 0.45 kg has exactly 6 grams less mass; but a 0.456 kg block of gold would be much smaller than a 0.45 kg marshmallow.
Davinci painted... "The Mona Lisa".
25x4=100
If you put ice cubes in a bowl or whatever of hot water, the ice cube is sure to melt when put so says science.
First Baptist Church of Painted Post was created in 1915.