Another positive integer
A set is closed under a particular operation (like division, addition, subtraction, etc) if whenever two elements of the set are combined by the operation, the answer is always an element of the original set. Examples: I) The positive integers are closed under addition, because adding any two positive integers gives another positive integer. II) The integers are notclosed under division, because it is not true that an integer divided by an integer is an integer (as in the case of 1 divided by 5, for example). In this case, the answer depends on the definition of "whole numbers". If this term is taken to mean positive whole numbers (1, 2, 3, ...), then the answer is no, they are not closed under subtraction, because it is possible to subtract two positive whole numbers and get an answer that is not a positive whole number (as in the case of 1 - 10 = -9, which is not a positive whole number)
A Negative times or divided by a Positive equals a Negative A Negative times or divided by a Negative gives a Positive A Positive times or divided by a Negative gives a Negative A Positive times or Divided by a Positive gives a Positive Zero is neither Positive or Negative so anything times Zero is not Positive or Negative.
If the numbers have to be positive, at least one of the two factor must be 1. In that case the product will be greater than or equal to 1 and equal to the other factor.If the numbers can be negative, in addition to the first case, any product of a positive and a negative integer will be less than or equal to both of the two factors. The product is negative so it's automatically less than the positive factor. If the positive factor is 1, the product is equal to the negative factor; if the positive factor is > 1 the product is less than the negative factor. E.g.1 * -14 = -14 which is equal to -14 and less than 1-3 * 5 = -15, which is less than both 5 and -3
Any one of the sets of the form: {kz : where k is any fixed integer and z belongs to the set of all integers} Thus, k = 1 gives the set of all integers, k = 2 is the set of all even integers, k = 3 is the set of all multiples of 3, and so on. You might think that as k gets larger the sets become smaller because the gaps between numbers in the set increases. However, it is easy to prove that the cardinality of each of these infinite sets is the same.
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A set is closed under a particular operation (like division, addition, subtraction, etc) if whenever two elements of the set are combined by the operation, the answer is always an element of the original set. Examples: I) The positive integers are closed under addition, because adding any two positive integers gives another positive integer. II) The integers are notclosed under division, because it is not true that an integer divided by an integer is an integer (as in the case of 1 divided by 5, for example). In this case, the answer depends on the definition of "whole numbers". If this term is taken to mean positive whole numbers (1, 2, 3, ...), then the answer is no, they are not closed under subtraction, because it is possible to subtract two positive whole numbers and get an answer that is not a positive whole number (as in the case of 1 - 10 = -9, which is not a positive whole number)
Negative. Sorry. No you do not. Adding a negative to a negative gives you a number that is even more negative. Picture a number line. A negative number is to the left of zero, and adding a negative number moves further left. ■
Look at it the other way - by reverting the operation. The reason it is not a whole number is because if it where, then the subtraction of two integers would be a fraction! If a + b = c (a is a non-integer fraction, b and c are integers), then c - b = a. You would have a fraction as a result of subtracting two integers. However, adding or subtracting two integers always gives you an integer.
Take any negative integers, say -5 and -10, their sum is -15 which is smaller than both of them. We could have used 0 as well, so I should have said any non-positive integers. To see that is does not work with positive integers, take 5 and 10 whose sum is 15 which is BIGGER than either one.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
The four possible combinations are:A = (+, +)B = (+, -)C = (-, +) andD = (-, -)In A and D, the two numbers have the same signs and the multiplication gives a positive answer.In B and C, the two numbers have different signs and the multiplication gives a negative answer.
Adding all integers from 33 to 112 inclusive gives you 5800.
Let x = 1st integer, since consecutive even integer differs by 2 then the 2nd integer = x + 2. So we have, x + 4(x + 2) = 48 x + 4x + 8 = 48 5x = 40 x = 8 (1st integer) Thus, the integers are 8 and 10. Check.
The square root of 5 is the positive real number that, when multiplied by itself, gives the prime number 5.
Adding two negative numbers always gives a negative number.
Just multiply the two numbers. Remember that multiplying two negative numbers gives a positive result.
900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.