The factors of 9 are 1, 3, and 9. The multiples of 9 are 9, 18, 27, 36, 45,...etc.
The multiples of 9 and factors of 36 are...... 9, 18, and 36
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.
To find the number of 4-digit numbers that are multiples of 9, we first determine the range of 4-digit numbers, which is from 1000 to 9999. Next, we calculate the first and last multiples of 9 within this range, which are 1008 and 9999 respectively. To find the total number of multiples of 9 in this range, we divide the difference between the last and first multiples by 9 and add 1, resulting in (9999 - 1008) / 9 + 1 = 999. Therefore, there are 999 4-digit numbers that are multiples of 9.
Hiya, first 3 even multiples of 9 are: 18, 36, 54 -hope this helped.
Yes, all multiples of 9 are also multiples of 3.but they're not all of them. Every multiple of 9 is also a multiple of 3, but there are more multiples of 3 besides those.
Common multiples of 9 and 10 are all of the multiples of 90.
All multiples of 18 are divisible by 9. Not all multiples of 9 are divisible by 18.
There are infinitely many multiples of 9 and it is not possible to add them all.
yes since 9 is divisible by 3 all its multiples are as well
All multiples of 90.
They are all multiples of 3.
18 and all the multiples of 18.
This question is true
They're all multiples of 9.
Well, honey, let me break it down for you. No, not all multiples of 9 are multiples of 6. See, multiples of 9 are numbers like 9, 18, 27, and so on, while multiples of 6 are numbers like 6, 12, 18, and so forth. So, while 18 is both a multiple of 9 and 6, not all multiples of 9 will be multiples of 6. Hope that clears things up for ya!
Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.