The factors of 9 are 1, 3, and 9. The multiples of 9 are 9, 18, 27, 36, 45,...etc.
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.
Well, honey, to find the number of 4-digit multiples of 9, you just need to divide the largest 4-digit multiple of 9 (9999) by 9 and subtract the smallest 4-digit multiple of 9 (1008) divided by 9. So, 9999 รท 9 - 1008 รท 9 = 1111 - 112 = 999. That's right, there are 999 4-digit numbers that are multiples of 9.
Multiples of 9 that are factors of 36 include 9 and 18. A multiple of a number is any number that can be divided by that number without leaving a remainder. A factor of a number is a number that divides the original number without leaving a remainder. In this case, 9 and 18 are both multiples of 9 and factors of 36 because they can be divided evenly into 36.
Hiya, first 3 even multiples of 9 are: 18, 36, 54 -hope this helped.
Yes, all multiples of 9 are also multiples of 3.but they're not all of them. Every multiple of 9 is also a multiple of 3, but there are more multiples of 3 besides those.
Common multiples of 9 and 10 are all of the multiples of 90.
All multiples of 18 are divisible by 9. Not all multiples of 9 are divisible by 18.
There are infinitely many multiples of 9 and it is not possible to add them all.
yes since 9 is divisible by 3 all its multiples are as well
All multiples of 90.
They are all multiples of 3.
18 and all the multiples of 18.
This question is true
They're all multiples of 9.
Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.
First of all unless you go into decimals, there are only three multiples of 9 and they are 1,3,and 9.