NO!
Quadrant 1 is top right (x,y) Both positive
Quadrant 2 is top left ( -x,y) ('x' is negative, 'y' is positive)
Quadrant 3 is bottom left (-x,-y)(Both negative)
Quadrant 4 is bottom right ( x,-y). ( 'x' is positive , and 'y' is negative).
no, they are both positive.
It is a horizontal line that intersects the y axis at negative 1
-1
It depends on the number of variables and their nature: 2 variables, both independent: either axis 2 variables, one independent: x-axis 3 variables, all independent: any axis 3 variables, 2 independent: x or y-axis. 3 variables, 1 independent: x-axis. and so on.
Multiply both by -1, (therefore not changing the result) and the calculation now equals a negative divided by a positive, which is negative. (Half a deficit, is still a deficit)
no, they are both positive.
It is a horizontal line that intersects the y axis at negative 1
both are 1s are negative and negative multiply negative = positive
I don't what you are asking, but both equations are parallel. They go by the same pattern (two y units up, 1 x unit right.) but one crosses the y axis at 0 and the other one crosses the y axis at negative 1.
x = negative 1 is a vertical straight line parallel to the y axis at x = -1 ; its slope is infinite
Some lines does not touch the x-axis or y-axis. For example, when the equation of line is y=1, the line never touches the y-axis [coordinates on the line would be (_,1)]. Equations such as y=1/x will not touch both axis.
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
-1
The numbers 1 and negative 1 (-1) are both square roots of positive 1.The square root of negative 1 is the "imaginary" number i.
-2/-2 = 1 Both of the negative signs cancel, leaving you with a positive one.1
both negatives will be canceled and answer will be positive
I assume the question is about cos x = -1. While it is true that cos x is negative in both the second and third quadrants, it reaches the value of -1 where the two quadrants meet, not inside the quadrants. The point where they meet is on the [negative] horizontal axis and x is -pi radians.