To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
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88cm2, but it's a rectangle, not a square.
It is either a triangle on a curved surface or a polygon with 4 or more sides.
60 cm2
12 square cm
No because the dimensions given relate to an isosceles triangle.
If one side of the triangle is 8cm then the other side is 7cm because 0.5*8*7 = 28 square cm
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
Area of a triangle = 1/2 * base * heightWe have,Area = 28 cm squared, base = 8cmthen,28 = 1/2 * 8 * h28 = 4*hh = 7cm
88cm2, but it's a rectangle, not a square.
11 x 8 = 88
The area for a 7cm by 8cm is 56.
The area of triangle is : 24.0
The area of triangle is : 44.0
The area of triangle is : 56.0
The area is 12cm2
It is either a triangle on a curved surface or a polygon with 4 or more sides.
The area of triangle is : 24.0