60C2 =( 60 x 59)/(2 x 1) = 30 x 59 = 1,770 handshakes.
Wow
35 divided by 5 = 7 7= one fifth of the students, so 3 fifths of the students = 21
"Each other" leaves this very open-ended; that depends on if A shakes with B or A shakes with B & C, OR if A shakes with all the other nine, etc. I would say the answer would have to be one of two: 10 or 100. If each person chooses only one to shake with, it would be ten. IF each person shakes with everyone there, all ten, it would be 100. Since this question is pretty vague, Some people may come to the conclusion that the answer is Either 90 assuming everybody stayed to shake hands with each other meaning the first person shook hands with 9 people and the 2nd person did the same etc etc bringing it to the conclusion that you got 90 handshakes. Another answer towards for people would be 45 being that the first person gave a hand shake to 9 people and then left and then the 2nd person gave a handshake to 8 people n then left etc and etc making it 9+8+7+6+5+4+3+2+1=45. A very simple formula can be applied here. no. of handshakes= (n(n-1))/2 where n is the no.of people present Another conclusion i think the answer is, is the simplest conclusion you can come up with; at the end of the banquet 10 people shake hands with each other so how many handshakes were passed on? 5 hand shakes were given cause that way 10 people did give a hand shakes and since it takes 2 to give out a handshake 5 hand shakes were given. The phrase "Each other" is inclusive, meaning that every person shakes the hand of every other person at the end of the banquet. And since the handshakes that occur when person 1 shakes person 2's hand and vice versa, are the same handshake, those handshakes only count as one entire handshake. This holds true with every other handshake between every other person at the banquet. With this is mind, there will be 45 handshakes since person 1 will shake 9 other people' hands, then person 2 will shake 8 other people's hands, and so on. It would look like this on paper: 9+8+7+6+5+4+3+2+1=45. Each of the 10 people shakes hands with 9 others. If you multiply that, you are counting each handshake double. Therefore, the calculation is 10 x 9 / 2.
Each person shakes hands with every other person at the end of the banquet. When person 1 shakes hands with person 2 that constitutes one handshake even though 2 people are involved. So the answer is 10 total handshakes because the 1st person will have 4 total handshakes(because he can't shake hands with himself, he has 4 and not 5 total handshakes), and then the 2nd person will have 3 total handshakes (you wouldn't say 4 handshakes because you've already included the handshake between person 1 & person 2 when calculating the first person's number of shakes) and so on for the remaining 3 people. On paper the math would look like this: 4+3+2+1=10 Alternatively: Each person shakes hands with 4 others so the answer looks like 5x4 = 20; However, in Fred shaking with 4 others, he shakes with Charlie, similarly, in Charlie shaking with 4 others he shakes with Fred. Thus the Fred-Charlie handshake has been counted twice (once by Fred, once by Charlie), as have all the handshakes, thus the answer is: 5x4 / 2 = 10.
(12 x 11 x 10 x 9)/(4 x 3 x 2 x 1) = 11,880/24 = 495 different groups.Three groups every time.495/3 = 165 ways for the different groups to stand.
Yes. Every even number has a factor of 2.
To the dignitaries on Dias, and all my friends. Every special moment comes to an end and this occasion is not an exception. We rejoin to part and take home the memories of the time we have spent in our institution. Every day has a night to assure that it will return again. This is the time when we say that. Though your part in our institution is over, your memories and your dedications will always remain pristine. We thank all the dignitaries for giving us their precious time, and all our outgoing friends who accepted our invitation and made this a memorable occasion.
25 shakes
If there are seven people, then the number of handshakes is 7*6/2 = 21
How many students out of every 100 students get accepted to cal state fullerton?
If there are 6 people in a room, and each person shakes hands with every otherperson in the room, then there will be 15 separate and distinct handshakesbetween different pairs of people.
Carla the Comeback Queen Insults for Every Occasion - 2004 V is rated/received certificates of: UK:PG
good ............... to the dignitaries on Dias, and all my friends. every special moment comes to an end and this occasion is not an exception. we rejoin to part and take home the memories of the best time we had spent in our institution. every day has a night, to assure that it will return again. this is the time when we say that- may your part in our institution is over but, your memories and your dedications will always remain pristine. we thank all the dignitaries to give us their precious time. and all our out going friends who accepted our invitation and made this a memorable occasion.
All I want for Christmas
Every night before bed, get on shakes and fidget go to the city guard and select ten hours. when you get back on the next day, harvest your money.
On every special occasion, my family gathers together to celebrate with good food and laughter.
72
A Line for Every Occasion - 2004 was released on: USA: 28 March 2004 (Los Angeles, California) Australia: 29 September 2004 (Alice Springs, Northern Territory)