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Yes, there can be a pure imaginary imaginary solution, as i2 =-1 and -i2 = 1. Or there can be a pure real solution or there can be a complex solution.
For a quadratic equation ax2+ bx + c = 0, it depends on the value of the discriminant [b2 - 4ac], which is the value inside the radical of the quadratic formula.
- [b2 - 4ac] > 0 : Two distinct real solutions.
- [b2 - 4ac] = 0 : Two equal real solutions (double root).
- [b2 - 4ac] < 0 : Two complex solutions; they will be pure imaginary if b = 0, they will have both real and imaginary parts if b is nonzero.
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How do you know if a quadratic equation will have more than one solutions?
Write the quadratic equation in the standard form: ax2 + bx + c = 0 Then calculate the discriminant = b2 - 4ac If the discriminant is greater than zero, there are two distinct real solutions. If the discriminant is zero, there is one real solution. If the discriminany is less than zero, there are no real solutions (there will be two distinct imaginary solutions).
If the discriminant of an equation is zero then?
The term "discriminant" is usually used for quadratic equations. If the discriminant is zero, then the equation has exactly one solution.
Is one solution to a real-world problem involving a quadratic equation always extraneous?
No. Sometimes they are both extraneous.
If the discriminant of a quadratic equation is -4 how many solutions does the equation have?
If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.
If the discriminant of a quadratic equation is greater than zero which is true A) It has one real solution. B) It has two complex solutions. C) It has two real solutions?
C
