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Well, isn't that just a happy little question! To find the antilog of a negative number using a log table, you can start by taking the absolute value of the negative number to make it positive. Then, look up the positive number in the log table to find its corresponding antilog. Remember, there are no mistakes in math, just happy little accidents!

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BobBot

2mo ago

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How do you find d antilog of a negative term?

The antilog? a log is an exponent, so as an antilog just means you reapply that exponent to the correct base. Log implies base 10, so antilog means use that number as an exponent of 10. If you are using log tables, first separate the whole number part and the decimal part of the log ( they are both negative) then add -1 to the whole number part and +1 to the decimal part. (one is called the characteristic and the other is called the mantissa, but I don't remember which is which now) This creates a positive decimal that you can look up in the log table. The negative integer part becomes an exponent of 10. Put them together and you get an answer in scientific notation. Ex: find antilog of -3.5 (-3 -1) + (-.5 + 1) ==> (-4) + (+.5) look up .5 in the log tables and you get 3.1623 and the -4 becomes 10-4 Put them together by multiplying (adding logs means multiplication of antilogs) to get the final answer 3.1623 x 10-4


How can you find the antilog of 0.0259?

To find the antilog of 0.0259, you can use the formula (10^{x}), where (x) is the value for which you want to find the antilog. In this case, calculate (10^{0.0259}). Using a calculator, you will find that the antilog of 0.0259 is approximately 1.058.


How to convert log values into antilog values?

1.Using calculator-press the 'shift' button and then the log number to be converted. N:B:Estimate answer to 3 s.f 2.You can also fin antilog by raising the log by power 10.e.g antilog of x is 10^x


Using logs what is 632x85.3?

632x85.3 = 53909.6


How do you divide 3533 by 9043 using log table?

Subtract the log of the divisor from the log of the dividend and then us the antilog table to find the value of the quotient.When using log tables:It is easiest to use logs to base 10;write the numbers in scientific notation, rounding to significant figures equal to the number of figures of the table;look up the mantissa (the bit before the × 10ⁿ) in the log table to get a value between 0 and 1;consider the exponent (the power of 10) as a number to be added to this log value;do the subtraction in two separate parts: subtract the whole numbers and subtract the fractional part (after the decimal point);if the fractional part is negative, add 1 to it to make it positive and subtract 1 from the whole number;look up the fractional part in the antilog table;multiply this value by 10 to the power of the whole number.Instead of rounding to the figures of the table, you can interpolate between the values in the table, but it is likely to not make much difference to the final value, which is only accurate to a maximum of the figures of the table.When adding the exponent to the looked up log value, if it is negative, write is as the absolute value with a bar over it. This is not a strictly correct use of the decimal point - it is really writing something like -1 + 0.345 in a compact form; the point is that the part after the decimal point is always positive whereas the whole number part is the part which may be negative.If you do not have antilog tables, you can find the antilog by finding the log value inside the table and finding the value in the headings.eg in my 3 figure tables, the log of 3.45 is looked up by finding where row 3.4 intercepts column 5 giving a value of 538 which is 0.538.To find the antilog of 0.307 I find 307 in row 2.0 under column 3 meaning the antilog of 0.307 is 2.03If the exact value does not appear in the table, you can interpolate between values to get the closest approximation. eg the antilog of 0.308: 307 → 2.03, 310 → 2.04; 308 is closest to 307, so the antilog to 3 figures would be 2.03Using 3 figure logs to base 10:3533 ÷ 9043 = (3.533 × 10³) ÷ (9.043 × 10³)= 10^(lg(3.533 × 10³) - lg(9.043 × 10³))≈ 10^(lg(3.53 × 10³) - lg(9.04 × 10³))≈ 10^((3 + 0.548) - (3 + 0.956))= 10^(0 - 0.408)= 10^((0 - 1) + (1 - 0.408))= 10^(-1 + 0.592)≈ 3.91 × 10⁻¹= 0.391(Using a calculator I get 3533 ÷ 9043 = 0.39068893..... which to 3 sig fig is 0.391 as found using the log table.)-------------------------------------------------A slide rule is an analogue log table.


How do you find logs of a number?

First you must decide what basis you are using for logarithms. Often this will be the number 10, or the number e. (In theory, any number greater than 1 will work.) Then you just raise the base to your number. For example, the antilog (base-10) of 5 is simply 105 = 100,000. Your scientific calculator should have an antilog key.


What is the antilog of -0.9?

The antilogarithm of -0.9 can be calculated using the formula (10^{-0.9}). This evaluates to approximately 0.1259. Therefore, the antilog of -0.9 is about 0.1259.


What sentence can you make using the words periodic table and nucleus?

The periodic table organizes elements based on their number of protons in the nucleus.


How do you find anti log of a number?

First you must decide what basis you are using for logarithms. Often this will be the number 10, or the number e. (In theory, any number greater than 1 will work.) Then you just raise the base to your number. For example, the antilog (base-10) of 5 is simply 105 = 100,000. Your scientific calculator should have an antilog key.


What is the answer of antilog of 7.98?

Roughly 95,499,258.6


How do you find cube of a number using log?

If log(x) = y then log(x3) = 3*log(x) = 3*y so that x3 = antilog(3*y) So, to find the cibe of x 1) find log x 2) multiply it by 3 3) take the antilog of the result.


Is negative 14 greater than negative 24?

Yes it is greater. When counting in negative number or using them in math, the smaller the negative number, the bigger it is