Sure, you can (a = 9, b = 0, c = -144). However, in this case, since there is no linear term, it is easier to transfer the -144 to the right (9x2 = 144), then take the square root on both sides. Don't forget to add "plus or minus" before one of the terms, or you will miss one of the two solutions.
All you do is set the quadratic function to equal to 0. Then you can either factor or use the quadratic formula to solve for your unknown variable.
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
Using the quadratic equation formula: x = 8.42 or x = -1.42
The quadratic formula can be derived by used a method called completing the square. It's like using algebra to solve for x. The process is explained the related link "Derivation of Quadratic Formula".
You convert the equation to the form: ax2 + bx + c = 0, replace the numeric values (a, b, c) in the quadratic formula, and calculate.
Solve using the quadratic formula
to solve ax2 + bx + c use the quadratic formula: (-b +/-(b2 - 4ac))/2a. Programming this should be a doddle.
Quadratic equation formula
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
If you can't factor it easily, use the quadratic formula.
If you can't factor it easily, use the quadratic formula.
The Quadratic formula in mathematics is used to solve quadratic equations in algebra. The simplest way to solve these equations is to set each of the factors to zero and then solve each factor separately.
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
It can be solved by using the quadratic equation formula.
X= (3/5 , -2)