0
NO!!!!
sqrt(-n) ?????
However,
-n X -n = (+)n^2
Sqrt(n^2) = either -n or (+)n , because either -n X -n = (+)n^2 or n x n = n^2
However,
sqrt(-n) takes us into IMAGINARY numbers.
sqrt(-n) = sqrt( -1 x n) = sqrt(-1) X sqrt(n)
.The sqrt(-1) is mathemtically unresolved and is given the symbol 'i' (small / lower case letter 'i'.
The sqrt(n) .being positive can be found.
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The square root of a negative number is considered an imaginary number, denoted as "i". In this case, the square root of -3 would be √(-3) = √3 * i. Therefore, the square root of -3 is not a real number, as real numbers are those that can be represented on the number line without involving "i".
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square roots of a negative number are imaginary, where i = square root (-1) sqrt (-2500) = sqrt (2500) i = 50 i
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To take the square root would be like asking: What number multiplied by itself would get this number? So for example, 5 multiplied by itself would equal 25, so the square root of 25 is 5.
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