0
NO!!!!
sqrt(-n) ?????
However,
-n X -n = (+)n^2
Sqrt(n^2) = either -n or (+)n , because either -n X -n = (+)n^2 or n x n = n^2
However,
sqrt(-n) takes us into IMAGINARY numbers.
sqrt(-n) = sqrt( -1 x n) = sqrt(-1) X sqrt(n)
.The sqrt(-1) is mathemtically unresolved and is given the symbol 'i' (small / lower case letter 'i'.
The sqrt(n) .being positive can be found.
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Is the square root of negative 3 an irrational or a real number?
The square root of a negative number is considered an imaginary number, denoted as "i". In this case, the square root of -3 would be √(-3) = √3 * i. Therefore, the square root of -3 is not a real number, as real numbers are those that can be represented on the number line without involving "i".
What is the square root of negative 2500?
square roots of a negative number are imaginary, where i = square root (-1) sqrt (-2500) = sqrt (2500) i = 50 i
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If you square an expression and then take the square root, the squaring and the square root cancel one another, EXCEPT that the sign will be positive. Thus, if you square 16x, and then take the square root, the answer can be 16x or -16x, depending on whether "x" is positive or negative. Or if you only square x, and then take the square root of the entire expression, it would be 4x or -4x (once again, depending on whether "x" is positive or negative).
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To take the square root would be like asking: What number multiplied by itself would get this number? So for example, 5 multiplied by itself would equal 25, so the square root of 25 is 5.
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