The circumference of a 24cm circle is: 75.4 cm(diameter x pi = circumference).
Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.
Since an isosceles triangle can be represented by two right triangles back to back, you can utilize the pythagorean theorum to solve this example. Specifically: 18cm/2 = 9cm = 1 leg of right triangle (A) 24cm = hypotenuse of right triangle (C) A squared + B squared = C squared Altitude = B = square root of (C squared - A squared) = approximately 19.875
A = 1/2 BH A = 24 = 1/2 BH 24 * 2 = BH 48 = BH H = B - 2 48 = B(B - 2) B2 - 2B = 48 B2 - 2B - 48 = 0 (B - 8)(B + 6) = 0 B = 8 or -6 Since the base cannot be negative, the base is 8 and the height is 6 (8 - 2)
10 mm = 1 cm 240 mm = 240/10 = 24 cm
24cm each
1/2*base*10 = 120 base*10 = 240 base = 24cm
The diagonal is 26cm
The area is 0.5*24*10 = 120 square cm. The third side is sqrt(24^2 + 10^2) = 26 cm. So the perimeter is 60 cm.
sqrt( 102 + 242 ) = sqrt( 100+ 576 ) = sqrt( 676 ) = 26 cm
Yes. Start with a regular one and distort it by changing angles and lengths of sides.
Yes because the given dimensions complies with Pythagoras' theorem for a right angle triangle.
The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm
The circumference of a 24cm circle is: 75.4 cm(diameter x pi = circumference).
You see you can do is 72cm divide by 3 because an equilateral triangle has 3 sides 72cm/3 = 24cm (I am not sure if this is right)
24cm
24cm